ok it is about 738 feet long
The square of the diagonal minus the square of the height would equal the square of the width. Therefore the square root of the solution to the above problem would be the width
Length is 12ft, width is 4 ft. 2 x (length + width) = perimeter = 32 ft ⇒ length = 16ft - width [1] length x width = area = 48 sq ft Using [1] above: ⇒ (16ft - width) x width = 48 sq ft multiplying out and rearranging: ⇒ width2 - 16 x width + 48 = 0 factorizing: ⇒ (width - 4)x(width - 12) = 0 Thus width = 4 or 12, so using [1] above: ⇒ width = 4ft, length = 16 - 4 = 12ft or width = 12ft, length = 16 - 12 = 4ft Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.
none of the above
Say you have a tire size 205/60HR16:205 is the section width of the tire in millimeters. Section width is the overall width from sidewall to sidewall. Tread width is typically 90% of the section width. In the above size, the section width is 205mm.The second number is the aspect ratio. This is the percentage ratio of the sidewall height to section width. In the above example, the sidewall height is 60% of the section width.The last number is the wheel diameter in inches. So in the above example, the wheel diameter is 16 inches.The R in the size designation means the tire is a radial tire, as almost all car tires are. The letter in front of the R (H in the above example) is the speed rating of the tire. The speed rating is the maximum speed the manufacturer recommends for the tire.
Although there are no reasons to support such an assumption, suppose the shape is a rectangle. Then perimeter = 2*(Length + Width) 70 = 2*(2 + width) 35 = 2 + width 33 = width. ie Width = 33 feet. Normally a length is larger than its width. It is therefore more than likely that the shape is not a rectangle and the above is based on an incorrect assumption.
Frogs are generally measured in length rather than height. The largest frog is the Goliath frog which can grow up to 33cm in length. It depends on the height and width.
n(Lenght)n(Width=X(Square Feet) In other words, Length times width equals square footage. ------------------------ The above answer is true only for a rectangle.
None of the above. A point only has a set of coordinates like (2,3).A point has no length, no width, no height, no dimension of any kind.A point has nothing but location.
It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.It enables you to change the width of a column, or the height of a row. It changes the width of the column to the left or the height of the row above.
The area of rectangle is : 7820.0
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
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