as the resistance/impedance of the the conducting wire is so small as compared to the load, there is a very low voltage drop across the conducting wires. keep the Ohm's law in mind i.e.
V=IR
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Agree- but making the conducting wires LONG enough, and there will be enough resistance for a voltage drop.
A thyristor if conducting will have a very small voltage drop across if not then the rail voltage will be evident across the device
No, even though these are parallel circuits, the voltage drop across each device is not the same in house hold circuits, or anywhere, for that matter. Different devices pull different currents. A toaster, for instance, pulls many times what a light bulb pulls. Since wires do not have truly zero resistance, those differing currents result in different voltage drops across the wires that lead to the devices. That small voltage drop in the wires results in a different voltage drop across each device, even though the device/wire is connected to the same voltage source.
A voltage drop in an electrical circuit is caused by resistance in the circuit components, such as wires, resistors, or other devices. This resistance reduces the flow of current and results in a decrease in voltage across the circuit.
The voltage drop across an LED varies, but is typically around 2 volts.
The increase in voltage from the main panel to the sub panel may be due to the resistance in the wires within the electrical system. As the current flows through the wires, there may be a voltage drop across the length of the wires, which can result in a slight increase in voltage at the sub panel. This phenomenon is known as voltage drop.
The thickness of a wire, also known as gauge size, can affect the resistance of the wire which in turn can affect the voltage drop across the wire when current flows through it. Thicker wires have lower resistance, resulting in less voltage drop compared to thinner wires for the same current flow.
The voltage measured across a dry cell is the total voltage output of the cell, typically around 1.5 volts. When three bulbs are connected in series, the total voltage drop across the bulbs will be the same as the voltage output of the dry cell. So, the voltage measured across the dry cell is equal to the voltage drop measured across the three bulbs in series.
A: Actually it begins to conduct almost as soon as there available current. but the current is such a low value that it is considered not to be conducting at all. And the 0.7 volts drop is a chosen value to indicate that the diode is fully conducting and the voltage drop across is .7 volts there about. It can have any value lower then that and it all depends on the current flowing at the time.
It doesn't. In a series circuit, the largest voltage drop occurs across the largest resistor; the smallest voltage drop occurs across the smallest resistor.
The voltage drop across a capacitor is directly proportional to the amount of charge stored in it. This means that as the charge stored in a capacitor increases, the voltage drop across it also increases.
The photodiode's voltage drop varies with the temperature and current flowing through it. The typical voltage drop (VBIAS - VREF) across the MAX4007 series is 0.8V, with a guaranteed maximum of 1.1V.
Voltage drop in a circuit is caused by the resistance in the wires and components, leading to a decrease in voltage as current flows through. To minimize voltage drop, use thicker wires with lower resistance, reduce the length of the wires, and use high-quality components. Additionally, ensure proper connections and avoid overloading the circuit.