Sizeof() is not needed because Java basic types sizes are fixed
There is no sizeOf() operator in Java.
Java does not have the sizeOf() operator or any operator that gives an equivalent result.
The sizeof operator is used to determine the length of its operand (in bytes). The operand must be a type or an object of a type (a variable). The operator is a constant expression and therefore executes at compile time. As such there is no runtime overhead in repeated use of the sizeof operator.
You cannot overload the sizeof() operator because that could introduce uncertainty in its evaluation. The sizeof() operator must always produce an accurate and logically predictable result, thus all user-intervention is completely forbidden.
C and C++ both include the built-in sizeof() operator to do just that.
The sizeof() operator returns the number of bytes allocated to the operand.
sizeof is not a keyword in Java but many classes have size() or length() methods, which can mean the number of elements, characters, etc. depending on the class.
Yes. The array name is a reference to the array, so you can use sizeof (name) / sizeof (name[0]) to determine the number of elements. Note that sizeof (name) alone gives the length of the array in bytes.
The sizeof() operator returns the number of bytes required to represent its argument.
In Java, the multiplication operator is represented by the asterisk, "*". This was not invented by Java; most programming languages, as well as programs such as Excel, use the same symbol.
Java does not have a sizeOf() operator and hence there is no way we can actually determine the size of a java class object. However we can analyze the overall heap space utilization to try to get an approximate indication of how much memory is used by an object but it is not accurate.
it is used to know the memory size of variable of data type. Ex: float a; printf ("sizeof (a)= %d\n", sizeof (a)); or: printf ("sizeof (float)= %d\n", sizeof (float));