Kirchoff's Voltage Law does not work, per se, for open circuits. You need a closed circuit for it to make any kind of sense.
The signed sum of the voltage drops going around a series circuit is equal to zero.
That means you have a closed circuit.
However, it can be argued, correctly, that an open circuit is simply one that has two nodes with infinite resistance between them. Assuming that all of the other nodes have something less than infinite resistance between them, then Kirchoff's law does work, of sorts, in that the voltage drop across all nodes that are not voltage sources will be zero, because there is no current, and the voltage drop across the two nodes with infinite resistance will be equal to the sum of the voltage rises across the voltage sources. Current sources in such a circuit will not work, because, with zero current, they would attempt to generate infinite voltage.
AnswerKirchhoff's Voltage Law does indeed apply to an open circuit, because the voltage drop across the open part of the circuit is numerically equal to the supply voltage and, hence, the algebraic sum of the voltage drops around that particular loop is zero.
Kirchoff's Voltage Law does not work, per se, for open circuits. You need a closed circuit for it to make any kind of sense.
The signed sum of the voltage drops going around a series circuit is equal to zero.
That means you have a closed circuit.
However, it can be argued, correctly, that an open circuit is simply one that has two nodes with infinite resistance between them. Assuming that all of the other nodes have something less than infinite resistance between them, then Kirchoff's law does work, of sorts, in that the voltage drop across all nodes that are not voltage sources will be zero, because there is no current, and the voltage drop across the two nodes with infinite resistance will be equal to the sum of the voltage rises across the voltage sources. Current sources in such a circuit will not work, because, with zero current, they would attempt to generate infinite voltage.
Read more: http://wiki.answers.com/Why_kirchhoff's_voltage_law_is_applicable_for_open_circuit#ixzz1i2fWNqfN
The full circuit voltage
The terminal voltage is equal to the supply voltage and there is zero current.
For answering this question we have to consider the constant voltage drop model of the diode which says that if voltage across diode is less then its cut in voltage than assume diode to be open circuit and if it is greater then assume diode to be short circuit.Till the input voltage is less than the cut in voltage, diode is open circuit(thus no current through the circuit). Thus entire input voltage appears across the diode as output.When input voltage is greater than or equal to cut in voltage, then short circuit the diode. Thus, there will be no voltage drop across the diode as output.Thus cut in voltage decides when to consider the diode open circuit and when short circuit. It decides when the diode will have output when it will not.
its likely to have the full supply voltage across it
Open circuit voltage is the voltage at the electrode before striking an arc (with no current being drawn). The higher the open circuit voltage, the easier it is to strike an arc because of the initial higher voltage pressure.
As load is conected in circuit , so thre is no open circuit therefore there would not be any open circuit voltage.
There is no particular benefit for having a higher open-circuit (or 'no-load') voltage. In fact, an ideal voltage source would have no internal resistance and, therefore, its open-circuit voltage would be identical to its closed-circuit voltage.
The voltage measured across an open in a series circuit is the equivalent of the sourse voltage.
The first thing you need to know is the internal resistance of the current source, the voltage source will have the same internal resistance. Then compute the open circuit voltage of the current source, this will be the voltage of the voltage source. You are now done.
Voltage is potential energy and can exist in a open circuit.
A: All batteries will eventually fail when that occurs the voltage out of then can be zero or higher voltage when new, In that case the battery has failed but if you measure the output it will have a higher voltage because there is no load or open circuit as soon as the load is applied the voltage just disappear this condition is called open circuit voltage
The voltage before it is hooked up to a resistive load.
The full circuit voltage
Three ways a circuit can be made to be open are, blown fuse, open switch and open contact.
Such a circuit either has no voltage source, or some part of the circuit is open, e.g., an open switch.
12v
The terminal voltage is equal to the supply voltage and there is zero current.