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The memory capacity of the 8085 microprocessor is 64 kb because the address bus is 16 bits, and you can address 216, or 64kb, with a 16 bit address bus.
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How many memory address can by address by 8085?
64 kb
How much memory in a commodore 64?
The Commodore 64 was equipped with 64 kilobytes (KB) or 65536 bytes of memory (64*1024). It was possible to expand this memory with a memory expansion plugged in the back although the 6510 CPU could only address 64 kb so these had methods for copying data up and down from the memory expansion to the system memory.
How much maximum memory size that 8085 can access?
Yes and no. All memory location from 0H to 0FFFFH are addressable, but some of them are needed for the program, interrupt vectors, and the stack, so you would need to pay attention to where things are located in memory to design an appropriate program. In addition, if your system is using memory mapped I/O, some locations will be reserved.
What are the disadvantages of 8085 microprocessor?
It works on 8 bit lower address lines has to be multiplexed with data lines Appropriate control signals have to be generated to interface with memory and I/O devices 8 bit processors are slow Memory is just 64 kb By Anmol Bhardwaj SUSCET Tangori Mohali ( India)
What is the cache memory of core 2 duo?
It has 64 KB of L1 cache per core and 4 MB of L2 cache.
How much space did the Intel 8080 microprocessor have?
The stack size of Intel's 8085 microprocessor is theoretically 64 kb, but the real limit is a function of memory and program architecture and layout. The stack pointer is 16 bits, but that is not the same as stack size.
What is the Meaning of KB in computer lingo?
KB = Kilo bytes which is equal to 1,000 bytes :)
What is the size of each memory segment of 8086 is?
The 8086 was only capable of addressing 1Mbyte of memory. It was divided into segments of 65536 bytes (64 KB) each meaning about 16 segments.
What is the expanded memory of a computer motherboard?
Expanded memory was to use part of the remaining 384 KB, normally dedicated to communication with peripherals, for program memory as well. In order to fit potentially much more memory than the 384 KB of free address space would allow, a bankingscheme was devised, where only selected portions of the additional memory would be accessible at the same time. Originally, a single 64 KB window of memory was possible; later this was made more flexible. Applications had to be written in a specific way in order to access expanded memory.
What does mb and kb stand for?
KB and MB stand for kilobyte (1,024 bytes) and megabyte (1,024 kilobytes). They are units of measurement of the storage capacity of computer memory, hard drives, USB sticks, DVD ROMs, etc.
What is minimum size of a segment in Intel 8086 Why?
In 8086 microprocessor the total memory addressing capability is 1 mega bytes. For representing 1 mb there are minimum 4 hex digits are required i.e, 20 bits. but 8086 has fourteen 16-bit registers. That is there are no registers for representing 20 bit address. So,the total memory is divided into 16 logical segments and each segment capacity is 64 kb(kilo bytes). That is 16*64kb=1 mb.So,for representing 64 kb only 16 bit register is sufficient. In 8086 microprocessor the total memory addressing capability is 1 mega bytes. For representing 1 mb there are minimum 4 hex digits are required i.e, 20 bits. but 8086 has fourteen 16-bit registers. That is there are no registers for representing 20 bit address. So,the total memory is divided into 16 logical segments and each segment size is 64 kb(kilo bytes). That is 16*64kb=1 mb.So,for representing 64 kb only 16 bit register is sufficient.
What is 8085 architecture?
8085 microprocessor is 8 bit microprocessor develop by Intel corp. it's architecture can be study broadly over internet various sites provide the information about architecture. some is given below 1-data bus - 8 2-address bus- 16 3-memory- 64 KB 4-GPRs - B,C D,E H,L 5-each of 8 bit 6- A L U. airthmatical logical unit.
