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When a negatively charged rod touches the sphere of the electroscope, negative sharge spreads throughout the metal. Since the leaves are both negatively charged, the free ends repel and move away from each other. When a positvely rod touchs the sphere, negative charges move toward the sphere, causing the leaves to be positively charged. hope this helps :)
In order to identify the charge of a body we should use a charged electroscope. Let us say the electroscope is negatively charged. Now bring the unknown charged body 'X' near the cap of the electroscope. If the leaves diverge more the charge in 'X' must be negative. Suppose that the leaves close a little when 'X' is brought near 'C', then 'X' may have a positive charge or it may not have any charge. In order to confirm the positive charge you must bring the rod 'X' near the cap of a positively charged electroscope. If the leaves diverge more, then 'X' has positive charge.
Step one. Charge the electroscope by the induction method. A rod is used of opposite sign to that required on the electroscope . The rod is brought near to the cap so that the leaf diverges by the amount desired, and the electroscope is momentarily earthed by touching it with a finger. The rod is then removed, leaving the electroscope charged. (If the charged rod used is Benoite this leaves a positively charged electroscope, if a glass rod is used then the result is negatively charged electroscope) Step two Now use the object of unknown charge, A charge of the same kind as that on the electroscope will cause an increase while a charge of the opposite kind will cause a decrease in leaf divergence when the object is brought near to the electroscope. You must bring the object down from a good height, and move it slowly down towards the cap so any change in divergence will not be overlooked before the object becomes to close to the cap. Bringing the object down too quickly and too close to the cap could lead to a false reading. Source(s): A. F. Abott Ordinary Level Physics
Assuming you mean an electrical conductor, No. To be a conductor, a material must have free electrons in the conduction band of the atoms. Metals have free electrons intrinsically in these bands, and so make great conductors. If you mean heat conductors, the answer is also no. Some objects are insulators of heat.
The ball in a pith ball elecroscope is small because the ball must be able to move with little forces. If the ball had a large mass it would be difficult for a small force of attraction to occur.
When a negatively charged rod touches the sphere of the electroscope, negative sharge spreads throughout the metal. Since the leaves are both negatively charged, the free ends repel and move away from each other. When a positvely rod touchs the sphere, negative charges move toward the sphere, causing the leaves to be positively charged. hope this helps :)
In order to identify the charge of a body we should use a charged electroscope. Let us say the electroscope is negatively charged. Now bring the unknown charged body 'X' near the cap of the electroscope. If the leaves diverge more the charge in 'X' must be negative. Suppose that the leaves close a little when 'X' is brought near 'C', then 'X' may have a positive charge or it may not have any charge. In order to confirm the positive charge you must bring the rod 'X' near the cap of a positively charged electroscope. If the leaves diverge more, then 'X' has positive charge.
Ampacity must be derated depending on the number of conductors and the ambient temperature. In the Canadian Electrical Code Table 5C denotes derating for the number of conductors. 1-3 conductors = 100% load 4-6 conductors = 80% 7-24 conductors = 70% 25-42 conductors = 60% 43 or more conductors = 50%
Conductors emerging from the ground must be enclosed in approved raceways. This is to protect the conductors from becoming damaged and starting a fire.
It must flow through the conductors.
600mm is the distance between two conductors in 11kv line
Question appears to be meaningless.
if assumed a hollow conductor, it must be INFINITE
Your question is unclear. But, if you are asking what the relationship between voltage and the distance between conductors is, then the higher the voltage, the greater the distance must be.
The radius must be increased by 26%. (rounded)
Step one. Charge the electroscope by the induction method. A rod is used of opposite sign to that required on the electroscope . The rod is brought near to the cap so that the leaf diverges by the amount desired, and the electroscope is momentarily earthed by touching it with a finger. The rod is then removed, leaving the electroscope charged. (If the charged rod used is Benoite this leaves a positively charged electroscope, if a glass rod is used then the result is negatively charged electroscope) Step two Now use the object of unknown charge, A charge of the same kind as that on the electroscope will cause an increase while a charge of the opposite kind will cause a decrease in leaf divergence when the object is brought near to the electroscope. You must bring the object down from a good height, and move it slowly down towards the cap so any change in divergence will not be overlooked before the object becomes to close to the cap. Bringing the object down too quickly and too close to the cap could lead to a false reading. Source(s): A. F. Abott Ordinary Level Physics
Let's be very careful here: The "great circle" of a sphere is a circle that lies on the surface ofthe sphere, so there's no way the great circle can "pass through" the sphere's center.However, in order for the circle to be a "great circle", its center must be the center of the sphere.