stanaderised of Na2S2O3 .
first we calculate the molecular weight M.W=158.11 mass of Na2S2O3=M.W*concentration*volume(in litter) for a concentration of 0.001 mass of Na2S2O3=158.11*0.001*1=0.15811 g so we use this mass and continue the volume to be 1 L
Na2S2O3 oxidation number
Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)
Oxidation no of sulphur is +2.
stanaderised of Na2S2O3 .
first we calculate the molecular weight M.W=158.11 mass of Na2S2O3=M.W*concentration*volume(in litter) for a concentration of 0.001 mass of Na2S2O3=158.11*0.001*1=0.15811 g so we use this mass and continue the volume to be 1 L
Na2S2O3 oxidation number
Sodium thiosulfate
Na2S2O3
+2
Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)
why flask keep in dark during standardization of na2s2o3 using k2cr2o7
Formula: Na2S2O3
Oxidation no of sulphur is +2.
Mol.Wt =248.17Molarity =( Wt/ Mol.Wt ) /No:of litres of solution0.1 =( Wt / 248.17) / 0.5Wt =0.1 *0.5*248.17Wt = 12.4085g in 500ml of solution.
the balanced equation is Na2S2O3 plus H2O2 yields 2NaOH plus H2S2O3 plus O2.