Oxygen has a lower electronegativity than fluorine (3.5 as compared to 4).
The second electron gain of an oxygen atom would be expected to be less negative. The reason for this outcome is that the oxygen atom gaining a second electron already has one electron and thus a negative charge. This negative charge repels the second electron to some extent, making the enthalpy of this process less negative than when the first electron was added to the neutral oxygen atom.
Oxygen is less dense.
The first scale of electronegativity was developed by Linus Pauling and on his scale helium has a value of no data on a scale running from from about 0.7 (an estimate for francium) to 2.20 (for hydrogen) to 3.98 (fluorine)
Bromine is less reactive than chlorine (and much less so than fluorine) so it is selective when it comes to halogenation substitution reactions.
I do believe, if my memory serves me correctly, that it is the elements in the first column.... they have only one atom on the outer shell, so it is less full.
Fluorine can not form oxyacids because fluorine is more electronegative than oxygen, and oxyacids are formed only from elements that are less electronegative than oxygen.
fluorine is the most electronegative atom . therefore atoms closer to fluorine will be more electronegative.
oxygen is more electronegative and so it wants the electron more than N
The second electron gain of an oxygen atom would be expected to be less negative. The reason for this outcome is that the oxygen atom gaining a second electron already has one electron and thus a negative charge. This negative charge repels the second electron to some extent, making the enthalpy of this process less negative than when the first electron was added to the neutral oxygen atom.
Fluorine is more electronegative than oxygen, so it's named as the anion. Chlorine is less electronegative than oxygen, so it's named as the cation.
both are in the same period which accounts for closeness. they are nonetheless different because there are more protons in the nucleus which means electrons are brought closer to it so there is a higher ionisation energy or potential
Lithium flouride is less soluble because the hydration enthalpy of lithiumflouride is less
The reason why fluorine has a higher ionization energy level than oxygen is because it is closer to the nucleus than is oxygen, therefore, it will take more energy to pull electrons from the nucleus.
The first Ionization energy of fluorine is less than that of the helium and neon.
Generally electron affinity goes up as you go from left to right across the periodic table, and decreases as you go down a column. However, fluorine is an exception -- and the element with the highest electron affinity is chlorine (note that the most electronegative element is fluorine however).The reason that the electron affinity is not as high as might otherwise be predicted for fluorine is that it is an extremely small atom, and so it's electron density is very high. Adding an additional electron is therefore not quite as favorable as for an element like chlorine where the electron density is slightly lower (due to electron-electron repulsion between the added electron and the other electrons in the electron cloud).Note that there are a number of other exceptions to the general rule of electron affinity increasing towards the upper right corner -- see the Related Questions links to the left for an explanation of some of those other exceptions.See also the Web Links to the left for more information about electron affinities and the fluorine-chlorine exception.
in water the electrons will be towards the oxygen since it is more electronegative than hydrogen so the repulsion between bp-bp will oppose the repulsion between lp-bp but in oxygenfluoride electrons will be towards fluorine so repulsion will be less so bond angle is less than water
Yes. It's true. Chlorine has the highest electron affinity, then Fluorine, Bromine and Iodine