Want this question answered?
No, a catalyst will not change reaction enthalpy. If it does so, then it is NOT a catalyst but a reactant in stead!
As the gas flow from high pressure to low pressure using the porous plug the temperature of the gas increases as the pressure of the gas decreases. As we know in all this process the enthalpy is constant. As we know in all this process the enthalpy is constant . So, to stay it constant the internal energy increases which lead to increase in temperature of the gas. Formula h=u+pv h--- enthalpy u-- internal energy p--pressure v---volume
enthalpy change of solution=enthalpy change of hydration - enthalpy change of lattice
"Constant pressure" means the pressure must not change.
The presence of a catalyst affect the enthalpy change of a reaction is that catalysts do not alter the enthalpy change of a reaction. Catalysts only change the activation energy which starts the reaction.
Enthalpy
Enthalpy
Enthalpy-The heat added to or loss by a system at constant pressure
Yes it is possible, for example when water freezes there is a point when the temperature remains constant however energy is released as the water condenses.
The refrigerant is at constant pressure
No, a catalyst will not change reaction enthalpy. If it does so, then it is NOT a catalyst but a reactant in stead!
enthalpy, H
The Fusion is the change in enthalpy for the conversion of 1 mole or 1 gram of a solid to a liquid, at constant pressure and temperature and is usually denoted as ΔHfus.
the pressure remains the same
Cp = ΔH/ΔT = (ΔU+pΔV)/ΔT Where Cp is heat capacity at constant pressure, ΔH is enthalpy change, ΔT is temperature change, ΔU is total internal energy change, and pΔV is pressure multiplied by change in volume.
I'm pretty sure its when the pressure remains constant. When the pressure is constant: q=delta U + P delta V The equation for delta H is: delta H = delta U +P delta V Therefore, when pressure is constant: delta H = q I think...
As the gas flow from high pressure to low pressure using the porous plug the temperature of the gas increases as the pressure of the gas decreases. As we know in all this process the enthalpy is constant. As we know in all this process the enthalpy is constant . So, to stay it constant the internal energy increases which lead to increase in temperature of the gas. Formula h=u+pv h--- enthalpy u-- internal energy p--pressure v---volume