It depends on the electron configuration. Different metals have single electrode potential. They are both +ve and -ve. We use standard Hydrogen electrode whose potential is taken to be 0. Using that we can find half potential. Then right from that we get the total potential of a cell. So it is all natures work
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As size increases, the s/v ratio decreases-- the s/v ratio of a cubic cell 1mm on a side is 6, but the s/v ratio of a cubic cell 3mm on a side is only 2.
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125 v
A turns ratio of 2000 to 100 is a 20 to 1 reduction in voltage, so the secondary, if the primary is 220 V, must be 11 V.
The standard cell potential for a cell made from gold and copper is the difference in standard reduction potentials between the two metals. The standard reduction potential for gold is +1.50 V and for copper is +0.34 V. Therefore, the standard cell potential would be 1.50 V - 0.34 V = 1.16 V.
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54 = 69 - V subtract 54 from both sides 0 =15 - V add V to both sides V = 15 check 54 = 69 - 15 54 = 54
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The voltage of a galvanic cell can be calculated using the standard reduction potentials of the half-reactions involved. For a cell with copper (Cu) and magnesium (Mg), the standard reduction potential for Cu²⁺/Cu is +0.34 V, and for Mg²⁺/Mg, it is -2.37 V. The overall cell potential (E°cell) can be calculated as E°(cathode) - E°(anode), resulting in E°cell = 0.34 V - (-2.37 V) = 2.71 V. Therefore, the voltage of the galvanic cell with copper and magnesium is 2.71 V.
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This wants to know the volume. V=Bh V="pi"r2h V=3.14(10)2(15) V=3.14(100)(15) V=314(15) V=4710ft.3