Returning a value of 1 (or any value besides zero) from main indicates an error.
Prototyping is done (at least in C/C++) to declare a function and tell the compiler how to use it before the int main(void) part of the program is run. The function is declared after main and is usually done as a style thing. example int function(int); int main(void) { int anumber = 1; x = function(anumber); return 0; } int function(int number) { //do something return number; } et cetera et cetera...
return var_name; e.g int fun() { int x=...; return x; }
In C-programming: int main (void) { return 0; }
name ( parameters )example:int main (int argc, char **argv){int i;for (i=0; i
Example: int main (void) { puts ("Here is a function definition"); return 0; }
int main void (int argc, char *argv[]){int i;for (i=0; i
If you want to use prototype it has to be declared before main(). If you have a function of type double with one argument of type int (with name arg), and the function name is func, then we have:#include ...double func(int arg);...int main(...){...return 0;}...double func(int arg){...}
Pieces of program-code, they are identified by their names. Example for function-declaration: int main (void); Example for function-definition: int main (void) { puts ("Hello, world!"); return 0; }
int main (void) or int main(int a, char **p)
name ( parameters )example:int main (int argc, char **argv){int i;for (i=0; i
No, it should be int type or void.
Only if you pass a pointer to it, eg: void sub (int *into) { *into= 3; } int main (void) { int myvariable; sub (&myvariable); return 0; }