while running, a slip ring induction motor ,it got tripped and found 2 nos power fuses blown out.on inspection rotor winding IR value zero.ie after releasing the brushes. how it happens?. pl ans
when the motor is starting its an induction motor with a squirrel cage
while its getting up to speed the voltage across the slip rings will be very high
there is a field resister shorting the rings this is removed and replaced with dc
with a make before break field application relay
if the dc is applied before the motor is up to near synchronous speed the stator will need to have very high current to accelerate the mass of the machine
sometimes the controls are magnetic
sometimes a centrifugal switch
sometimes a timer
a compressor will have an unloader to minimise load on the motor before the dc is applied
however this is done
if dc is on the field before you get close to operating speed you will blow fuses
if the "failure" happened while running it could be a momentary power interruption or a momentary load interruption
if the controls didnt see it and restart the motor
you can dissect the fuses and see weather you had a short or an overload
or add a bit more detail about the equipment and incident
No. un uniform air flux will cause imbalance in the shaft
This is how an induction motor normally works, hence the name. The supply voltage is connected to the stator winding(s) and a current is induced in the rotor. A synchronous motor, on the other hand, will have current supplied to the rotor through slip rings and brushes. The rotor current is generally supplied as DC though, or else rectified in the rotor.
A motors locked rotor current is the same as the motors starting current. This is the point where the voltage is applied to a non rotating motor, time cycle zero. Because the motor is not rotation and generating a back EMF to oppose the inrush current, the current will go as high as 6 times the running current of the motor.
Nr = NS * (1-s) Nr = rotational speed (rev/sec) Ns = Synch Speed (rev/sec) s = Slip (%)
Because power is needed to accelerate the rotor and thus increase its kinetic energy.
The direction an induction motor will turn depends upon the direction of the rotating field setup by the winding. Remember in AC the direction of the current reverses itself 120 times every second for a 60 hz system. So no it will not turn in the "direction" of the current.
Standard induction motor has a closed squirrel cage rotor, where as open ended induction motor has split phase rotor.
Induction motor is an AC electric motor which uses electromagnetic induction to induce the electric current in the rotor to produce torque.
explain wound rotor
short the rotor terminals.
The pullout torque is the maximum torque a motor can achieve. Also known as breakdown or peak torque. It occurs at the point where, the increase in the rotor current is exactly balanced by the decrease in the rotor power factor.
rotor speed = 0
Yes, the induction motor has a rotor winding. It is usually one turn, shorted. This is how the magnetic fields generated in the stator induce a current in the rotor, which subsequently generates a torque from the opposing magnetic fields, stator to rotor.
its impossible to give suppy to rotor of an induction motor,because of it a closed path for circulating currents.
rotor speed will decrease....the rotor current wil increase.....
rotor speed will decrease....the rotor current wil increase.....
Squirrel cage induction motors.
DOL(Direct Online starting) Star Delta starting Auto transformer starting Above methods are for squirrel cage induction motor Rotor resistance starting is used for wound rotor or slip ring induction motor