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Why the array is starting from zero?

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Anonymous

13y ago
Updated: 8/19/2019

By design; it makes the compiler's work easier.

1-based array's addressing-function:

Address (array, index) = Address (array) + (index-1)*Elemsize(array)

0-based array's addressing-function:

Address (array, index) = Address (array) + index*Elemsize (array)

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13y ago

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