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Without looking it up, I'll go out on a limb here and state my guess. (Then somebody else can come along and show that my guess was all wet.) I think angular velocity and acceleration are both right-hand-rule guys, with vectors formed by (R) cross (rotation direction). If true, and rotation is from west to east (counterclock viewed from above the north pole), then the angular velocity vector points into the south pole and out of the north pole. Correction: You have stated the true method for the answer above, but got the opposite answer. Since the earth rotates in a counter-clockwise direction viewed from the north pole, the angular velocity vector would point from the center of the earth to the north pole. It's magnitude would be the angular velocity of the earth's spin. -J I think that's exactly what I said ... " ... out of the north pole". Ah I see, my apologies. I think where I was confused was where you stated "into the south pole..." Instead you can state that it would originate from the center and point towards the north pole. You can rewrite it and delete our discussion :)
displacement
Angular unconformities separate rock layers along nonparallel surfaces
Mercury, just as Earth rotates alone its axis. The spin is from left to right along this axis with one rotation lasting nearly 176-days on Earth. Needless to say it is a very slow spin in comparison.
Angular velocity just means how fast it's rotating. If youaa want more angular velocity, just rotate it faster or decrease the radius (move it closer to the center of rotation). Just like force = rate of change of momentum, you have torque= rate of change of angular moment Or We can increase the angular velocity of a rotating particle by applying a tangential force(i.e. accelaration) on the particle. Since the velocity of the particle is tangential with the circle along which it is moving, the tangential accelaration will not change the diriction of the velocity(as angle is 0),but will cause a change in magnitude. Thus angular velocity will increase.
Yes, suppose a body is rotating anti-clockwise, then its angular velocity and angular momentum, at any moment are along axis of rotation in upward direction. And when body is rotating clockwise, its angular velocity and angular momentum are along axis of rotation in downward direction. This is regardless of the fact whether angular velocity of the body is increasing or decreasing.
angular velocity s the rotational analague of linear velocity...direction of linear velocity s along tangent to the circle while that of angulr velocity s along the axis of rotation.the direction of angular v can be find by right hand rule which state that if the axis of rotation s held n right hand with fingers curled round the direction of rotation then the thumb will mark the direction of angular velocity.... the magnitude of angular velocity that s the angular speed is represented by the length of the line along the axis of rotation...its units are rad/sec,degrees/sec or revolution/sec while that of linear velocity s m/sec...
Yes. The "direction" of the vector is along the axis of rotation.Yes. The "direction" of the vector is along the axis of rotation.Yes. The "direction" of the vector is along the axis of rotation.Yes. The "direction" of the vector is along the axis of rotation.
no answer
Displacement in any interval of time may be zero,positive or negative.Imagine that a car begins traveling along a road after starting from a specific signpost. To know the exact position of the car after it has traveled a given distance, you need to know not only the miles it traveled but also its heading.The displacement, defined as the change in position of the object, is a vector with the magnitude as a distance, such as 10 miles, and a direction, such as east. Velocity is a vector expression with a magnitude equal to the speed traveled and with an indicated direction of motion. For motion defined on a number line, a positive or negative sign specifies the direction.Average velocity is mathematically defined asaverage velocity = total displacement/time elapsedNote that displacement (distance from starting position) is not the same as distance traveled. If a car travels one mile east and then returns one mile west, to the same position, the total displacement is zero and so is the average velocity over this time period. Displacement is measured in units of length, such as meters or kilometers, and velocity is measured in units of length per time, such as meters/second (meters per second).
This applies to three-phase transformer connections. 'Phase shift' or 'angular displacement', is defined as 'the angle by which the secondary line-to-line voltage lags the primary line-to-line voltage'.Angular displacement depends on the type of transformer connection. The most common are:delta/delta results in an angular displacement of 0o or 180owye/wye results in an angular displacement of 0o or 180odelta/wye results in an angular displacement of 30o or 210owye/delta results in an angular displacement of 0o or 180oThe angular displacement for all possible combinations of three-phase transformer connections are listed in transformer vector group charts.Angular displacement determines whether or not it would be possible to parallel different types of three-phase transformer connections. For example, from the above data, it would be impossible to parallel, for example, a delta/delta transformer with a delta/wye transformer.
No. Cos theta (Cos θ) is a trigonometric function. A vector is any physical quantity which has both magnitude and direction. For example, Displacement. Displacement has a magnitude like 240m or 0 or 13 m, etc. It also depends on the direction. If an object moves along the positive direction of x-axis, then the displacement will have a positive sign and if it moves along the negative direction of x-axis, then displacement will be negative. Thus, it has both direction and magnitude and so is a vector. Cos theta is a trigonometric function, strictly speaking.
When an object rolls the center of gravity (or of geometry - or both depending on the shape of the object) translates (moves) along a path and there is a point of contact with a surface on the perimeter of the object, rotation (angular change) does occur too.During rotation the center of gravity could be motionless and there is probably no point of contact with any surface; the movement is purely angular.
It's a demonstration of their angular momentum vectors being aligned in almost the same direction. Laplace added up all the vectors for the planets (the angular momentum vector is directed along the axis of rotation) and defined an invariable plane for the solar system, which is a plane that stays the same all the time. Total angular momentum is conserved so this plane will never change, even though momentum might be exchanged between the planets as their orbits change slightly.
Scientists prefer to use the term "spin" rather than angular momentum. However, if one were to view an electron as a charged particle, spinning about its axis, but changing the direction of its axis of rotation so rapidly that only a fraction of its angular momentum points in any one direction at any time, then we could say the TOTAL angular momentum is sqrt(3) h-bar/2 where h-bar is Planck's Constant divided by 2 pi. and the angular momentum along one specific, external axis would be plus or minus h-bar over two.
Without looking it up, I'll go out on a limb here and state my guess. (Then somebody else can come along and show that my guess was all wet.) I think angular velocity and acceleration are both right-hand-rule guys, with vectors formed by (R) cross (rotation direction). If true, and rotation is from west to east (counterclock viewed from above the north pole), then the angular velocity vector points into the south pole and out of the north pole. Correction: You have stated the true method for the answer above, but got the opposite answer. Since the earth rotates in a counter-clockwise direction viewed from the north pole, the angular velocity vector would point from the center of the earth to the north pole. It's magnitude would be the angular velocity of the earth's spin. -J I think that's exactly what I said ... " ... out of the north pole". Ah I see, my apologies. I think where I was confused was where you stated "into the south pole..." Instead you can state that it would originate from the center and point towards the north pole. You can rewrite it and delete our discussion :)
Rotation around a point, or spherical motion, is the motion of a rigid body during which one of its points O remains fixed, while all the other points move along the surface of spheres with their center at point O. During such rotation of a rigid body, any elementary displacement of the body is an elementary rotation around some axis passing through point O and called the instantaneous axis of rotation. This axis, unlike a fixed axis, is constantly changing its direction with time. As a result, the rotational motion of a rigid body consists of a series of elementary rotations about instantaneous axes that are constantly changing direction. An example of such rotation is the movement of a gyroscope.