There is not enough information in the question to answer it. Please restate the question.
There are two input and output ports for Input 1 and 2 and Output 1 and 2.
The output depends on what x is. If x = 1, then y = 2.
cardiac output :)
The rule appears to be a linear relationship between the input and output values. When the input increases by 4 (from 1 to 5), the output decreases by 4 (from 5 to 1). Similarly, when the input increases by another 4 (from 5 to 9), the output decreases by 4 again (from 1 to -3). Therefore, the rule seems to be that for every increase of 4 in the input, the output decreases by 4.
2 input and 1 output
In AND gate , if through both the terminals minimum values were send then the output will be 0 . if either one of the input is maximum , then the output will be 0 , meanwhile if both the input were 1 then the output will be 1 .In OR gate , if both the input are 0 then the output will be 0, but if either the input is 1 then the output will be 1,when both the inputs are 1 then the output will be 1 .
PRINTER
An AND gate gives a 1 or True output only and only if all the inputs are True or 1. If even a single output is False or 0, it will not give any output meaning thereby that the output will be False or 0. A NAND gate is quite the reverse of an AND gate and gives an output of 1 or True only if both the inputs are not True or 1. This means that even when both inputs are 0 or False, it still gives a True or 1 output.
The types of VAT........ 1 ) INPUT VAT @ 4 % 2 ) INPUT VAT @ 1 % 3 ) INPUT VAT @ 12.5 % 4 ) OUTPUT VAT @ 1 % 5 ) OUTPUT VAT @ 4 % 6 ) OUTPUT VAT @ 12.5 %
An OR gate outputs a 1 when at least one of its inputs is 1. This means that if either input A or input B (or both) is high (1), the output will be high (1). If both inputs are 0, the output will be 0. Thus, the OR gate functions as a logical inclusive operator.
4000 yrs
an impedance common to both input and output can be slit into two (input alone and output alone) by using miller theorem.at the i/p side impedance multiplied by 1-gain and output side it is done by 1-1/gain.