call the numbers a & b
(a+b)2 = a2+2ab+b2
which is greater than a2 + b2 by twice the product of the numbers.
Check: say 3 and 5
32 + 52 = 9 + 25 = 34
(3 +5)2 = 64, greater by twice a x b. QED
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If a and b are the numbers, then (a+b)2 = a2 + 2ab + b2, which is different from a2 + b2 (not necessarily larger). The two quantities are equal only when one (or both) of a,b is zero.
5
sum of squares: 32 + 52 = 9 + 25 = 34 square of sum (3 + 5)2 = 82 = 64 This is a version of the Cauchy-Schwarz inequality.
They are 8 and 13.
x2 + y2 = (x + y)2 => x2 + y2 = x2 + 2xy + y2 => 2xy = 0 => xy = 0 So, one of x and y must be 0.
7 and 9 72+92 = 130
split 10 in two parts such that sum of their squares is 52. answer in full formula
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
Sum of squares? Product?
Not unless at least one of the numbers is zero.
25 is a square number, and the sum of 9 and 16 is 25. 9 and 16 are also square numbers.
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
For an array of numbers, it is the square of the sums divided by the sum of the squares.
1. Design an algorithm to compute sum of the squares of n numbers?
It squares numbers and add the totals together. The square of 2 is 4, the square of 5 is 25. The sum of squares of 2 and 5 is therefore 29. That would done in the SUMSQ function like this: =SUMSQ(2,5)
It is not clear what the question means: there are 31 2-digit numbers that can be expressed as a sum of two squares.
The sum of their squares is 10.
The one in which the square of the biggest one is equal to the sum of the squares of the other two is.