10 mg/ml stock solution
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
10-4
You need 6,9 mL stock solution.
You need to add the 50ul stock solution to 1200ul of distilled water to produce 1250ul of solution with a concentration of 2ul per ml.
10 mg/ml stock solution
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
10-4
Well to make 30% stock solution of BSA from powder form you need to dissolve 30g of BSA into 100ml of solvent (water). Thus dissolved solution becomes 30% (w/v) stock solution.
The answer is 20,15 mL.
You need 6,9 mL stock solution.
0.15g of leishman powder dissolved in 100ml of distilled water
This depends on your experiment.
If this is .020m solution, you need 3.81g If this is .20m solution, you need 38.1g If this is 20m solution, you need 3810g
(385 mL)(0.766 M NaOH) = (X mL)(4.03 M NaOH)4.03X = 294.91X = 73.2 ml============Take 73.2 mL of stock solution and add ( 385 mL - 73.2 mL = 311.8 mL) 312 mL of water to stock solution.
So you need a 1 in 5 dilution (5x dilution i.e. 0.5/0.1), so 100/5 is 20ml stock diluted to 100ml