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A TITRATION is a laboratory method used to determine the concentration of an acid or a food in a solution.
Arguably the most common neutralization reaction is the one that is used by individuals who take things to neutralize stomach acid. The acid the stomach produces is HCl, or hydrochloric acid, and bicarbonates (sodium or calcium) are frequently employed to neutralize some of it.
For preparation of standard solution of Mohr salt {FeSO4.(NH4)2SO4.6H2O}, it's necessary to add dilute H2SO4 to prevent the Fe2+ ions of Mohr salt solution from undergoing oxidation (to Fe3+). Just try to prepare the standard solution without adding this acid. You'll observe that your "Mohr solution" will become yellow in colour, i.e., it won't remain "Mohr salt solution" anymore, hence can't be used in titration. And while doing the titration of the Mohr salt solution with KMnO4 (or even with K2Cr2O7), you need to add dilute H2SO4. The reason is well explained by the chemical equation involved: reduction: (MnO4)- + 8H+ + 5e ----> Mn2+ + 4H2O oxidation: Fe2+ ----> Fe3+ + e net equation: (MnO4)- + 8H+ + 5Fe2+ ----> Mn2+ + 4H2O + 5Fe3+ There is involvement of H+ ions in this reaction. This redox titration requires acidic medium. Moreover, KMnO4 acts as a very good oxidizing agent in the presence of acidic medium, than in the basic and neutral medium. NOTE: Now a query may arise that for providing acidic medium, can HCl or HNO3 be used? (Let me tell you it's one of the favourite questions of external examiners) The answer is NO, because HNO3 is a very strong oxidizing agent. So, the Fe2+ present will be oxidized both by KMnO4 and HNO3, which will result in an error in determination of volume of KMnO4 reacting with Mohr salt solution. Also, HCl can't be used because Cl- from HCl will be oxidized by KMnO4: HCl (aq) ---> H+ (aq) +Cl- (aq) oxidation by KMnO4=> 2Cl- ----> Cl2 + 2e So, some extra KMnO4 will be used up because it will oxidize both- Cl- as well as Fe2+, => error in titration.
For preparation of standard solution of Mohr salt {FeSO4.(NH4)2SO4.6H2O}, it's necessary to add dilute H2SO4 to prevent the Fe2+ ions of Mohr salt solution from undergoing oxidation (to Fe3+). Just try to prepare the standard solution without adding this acid. You'll observe that your "Mohr solution" will become yellow in colour, i.e., it won't remain "Mohr salt solution" anymore, hence can't be used in titration. And while doing the titration of the Mohr salt solution with KMnO4 (or even with K2Cr2O7), you need to add dilute H2SO4. The reason is well explained by the chemical equation involved: reduction: (MnO4)- + 8H+ + 5e ----> Mn2+ + 4H2O oxidation: Fe2+ ----> Fe3+ + e net equation: (MnO4)- + 8H+ + 5Fe2+ ----> Mn2+ + 4H2O + 5Fe3+ There is involvement of H+ ions in this reaction. This redox titration requires acidic medium. Moreover, KMnO4 acts as a very good oxidizing agent in the presence of acidic medium, than in the basic and neutral medium. NOTE: Now a query may arise that for providing acidic medium, can HCl or HNO3 be used? (Let me tell you it's one of the favourite questions of external examiners) The answer is NO, because HNO3 is a very strong oxidizing agent. So, the Fe2+ present will be oxidized both by KMnO4 and HNO3, which will result in an error in determination of volume of KMnO4 reacting with Mohr salt solution. Also, HCl can't be used because Cl- from HCl will be oxidized by KMnO4: HCl (aq) ---> H+ (aq) +Cl- (aq) oxidation by KMnO4=> 2Cl- ----> Cl2 + 2e So, some extra KMnO4 will be used up because it will oxidize both- Cl- as well as Fe2+, => error in titration.
KOH is a strong base that disassociates almost completely in solution to form the salt and water needed in a neutralization reaction. Thus, KOH + HCl -> KCl + H2O
Yes, it can if you consult with a clinical ecologist or immunologist who uses the Miller Method of provocation and neutralization.
I may be off, but it has something to do with thermodynamics. The silver reacts well with chlorine and bromide, but when it comes to iodide, i would guess that the dG is too low leaving the iodide in solution. Also, if you look at the solubility of silver iodide, it is VERY high in water which doesn't give you the chance to create the precipitate needed for use in the Mohr method. Silver Chloride - white precipitate Silver Bromide - ? precipitate. Silver Chromate - red good luck.
screening
we can use neutralization is in tooth paste
A TITRATION is a laboratory method used to determine the concentration of an acid or a food in a solution.
filtration
The Bradford method involves a chemical test. It is used by scientists to determine the concentration of proteins in a solution.
Chromatography
I want to assmue the the readers of this answer have know the details theory and calculations about Mohr method if not u can refer to Any analytical text for reference. Well, Bromide and Chloride can not be determine simultaneously in a sample using Mohr method , the reason be that the indicator use for each of them is different. and there will be problem in the procedure if ones try to determine both simultaneously. To determine Chloride Ion, Ammonium or Potassium Thiocynate is used as indicator and the sample must be neutral or slightly acidic. while Eosin indicator is use for the determination of Bromide Ion and the same neutral solution is prefer for this purpose, the solution must be adjusted to neutral either by adding small amount of Nitric acid or by adding small amount of carbonate as the case maybe. But, in the determination of each of them Silver Nitrate is use for the titration of both and this is the similarity they shared and the experimental procedure is quite the same. Olajire Mojeed
Salt and water ..in neutralization water is a common product..salt formed will be from acid used
Arguably the most common neutralization reaction is the one that is used by individuals who take things to neutralize stomach acid. The acid the stomach produces is HCl, or hydrochloric acid, and bicarbonates (sodium or calcium) are frequently employed to neutralize some of it.
For preparation of standard solution of Mohr salt {FeSO4.(NH4)2SO4.6H2O}, it's necessary to add dilute H2SO4 to prevent the Fe2+ ions of Mohr salt solution from undergoing oxidation (to Fe3+). Just try to prepare the standard solution without adding this acid. You'll observe that your "Mohr solution" will become yellow in colour, i.e., it won't remain "Mohr salt solution" anymore, hence can't be used in titration. And while doing the titration of the Mohr salt solution with KMnO4 (or even with K2Cr2O7), you need to add dilute H2SO4. The reason is well explained by the chemical equation involved: reduction: (MnO4)- + 8H+ + 5e ----> Mn2+ + 4H2O oxidation: Fe2+ ----> Fe3+ + e net equation: (MnO4)- + 8H+ + 5Fe2+ ----> Mn2+ + 4H2O + 5Fe3+ There is involvement of H+ ions in this reaction. This redox titration requires acidic medium. Moreover, KMnO4 acts as a very good oxidizing agent in the presence of acidic medium, than in the basic and neutral medium. NOTE: Now a query may arise that for providing acidic medium, can HCl or HNO3 be used? (Let me tell you it's one of the favourite questions of external examiners) The answer is NO, because HNO3 is a very strong oxidizing agent. So, the Fe2+ present will be oxidized both by KMnO4 and HNO3, which will result in an error in determination of volume of KMnO4 reacting with Mohr salt solution. Also, HCl can't be used because Cl- from HCl will be oxidized by KMnO4: HCl (aq) ---> H+ (aq) +Cl- (aq) oxidation by KMnO4=> 2Cl- ----> Cl2 + 2e So, some extra KMnO4 will be used up because it will oxidize both- Cl- as well as Fe2+, => error in titration.