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An object floats when the buoyant force is equal to the object's weight. An object sinks when the buoyant force is less than the object's weight.
For the object to sink, the buoyant force has to be less than the weight. If the two forces are exactly equal, the object had neutral buoyancy.
The buoyant force is what causes and object to float. If the buoyant force is less than the object weight, it sinks. If the buoyant force is greater than the objects weight, it rises to the top. If it is equal, the object will float in the middle, neither rising or falling.
It can be, or it can be less than the weight of the object.The buoyant force is equal to the weight of the displaced fluid.
The same object is more buoyant in a denser fluid, and is more likely to float, than in a less dense one. That's why tennis balls float in water but not in air.
An object floats when the buoyant force is equal to the object's weight. An object sinks when the buoyant force is less than the object's weight.
For the object to sink, the buoyant force has to be less than the weight. If the two forces are exactly equal, the object had neutral buoyancy.
No.
The buoyant force is what causes and object to float. If the buoyant force is less than the object weight, it sinks. If the buoyant force is greater than the objects weight, it rises to the top. If it is equal, the object will float in the middle, neither rising or falling.
It can be, or it can be less than the weight of the object.The buoyant force is equal to the weight of the displaced fluid.
Of course. That's exactly the situation whenever an object sinks.
The object would float in a given liquid.
The object will sink in the fluid.
The object will sink in the fluid.
The same object is more buoyant in a denser fluid, and is more likely to float, than in a less dense one. That's why tennis balls float in water but not in air.
If you just set the object in the water, the buoyant force never becomes greater than the object's weight. It sinks and sinks, displacing more and more water, building up more and more buoyant force, until the buoyant force is equal to its weight. At that point, the net force on it is zero, it stops sinking, and it stays right there (floating). The only way you can produce a buoyant force greater than its weight is to force it further down and hold it there. Since the buoyant force is greater than its weight, as soon as you let go, the net force on it is up, and it'll rise, partly out of the water until the buoyant force drops to equal its weight, and again ... it'll stay right there. So the answer to the question is: An object can't stay indefinitely in a position where the buoyant force is greater than its weight. If that happens, then it lifts some of itself out of the water, reducing the buoyant force, until the buoyant force is again just equal to its weight.
The buoyant force is equal to the weight of water displaced. For a dense object, such as a coin or a bowling ball, the weight of the object is greater than the buoyant force and the object will sink if you let go of it. For a less dense object, such as an ice cube or a block of balsa wood, the buoyant force is greater than the weight and you can feel it pushing the object toward the surface, resisting your attempt to hold it submerged. If you let go, the object will rise up and float.