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it would be 100 - 35 = 65 m
0.712 m/s^2
That depends a lot on the type of waves you want to measure. For waves on water, you would measure the amplitude in meters, for sound waves you would use pressure units, for electromagnetic waves you would use either electric or magnetic units, etc.
A spring scale in itself does not measure mass; rather, it measures the amount of force (in Newtons) required to move an object. However, you can find the mass, provided you know the acceleration (how much the object is changing speed). Example: You use a spring scale on on object, and it gives you a measurement of 10 Newtons (N). To find the mass, you would use the following formula: m = f/a Where m is the mass (kilograms), f is the force (Newtons), and a is the acceleration (meters per second per second, or m/s2). So, if the force is 10N, and the acceleration (for the purposes of this example) is 5m/s2, then: m = 10/5 m = 2 So, the mass would be 2 kilograms (kg).
0.5 m in 2 hours would be 1 m per hour.
it would be 100 - 35 = 65 m
You would divide 250 miles by 12.5 to find out how many miles is one inch. So the scale would be 1 in = 20 m
because that's the scale the map is drawn at...
It is the same as 2 cm = 3 m or 1 cm = 1.5 m The scale ratio would therefore be 150:1
0.712 m/s^2
Assuming the y-axis represents distance from the finish line, and they both move at a constant velocity IOW v(t)=m(t)+b, the animal with the higher negative m-value will win every time. If the hare's velocity changes at times, then his average velocity would determine his finish time. If the hare's (v(t+h)-v(t))/h results in a higher negative slope than the turtle's, the hare would still win. .
a sign that says, "north, east, south, west"
If a star has some parallax - if its position against the background stars appears to be a teeny bit different in January than in July - then we know it's pretty close, and we can calculate precisely how far away it is.
The diameter of the entire model would be about 22 meters at the furthest points if your atom was a hydrogen atom. This is based upon the relative size of the different pieces of the nucleus, electrons and distance between them.
None. M, M and M are the same so they are coincident and, consequently, the distance around them is zero.
Suppose a set of observations for a variable X has a mean mx.If a scale factor of a is applied to the observations, and the origin is shifted to the left by a distance b, then the new mean will be (m/a)*x + b.
Multiply the distance in km by 1000 to get the distance in m.