Fluorine does not have the highest electron affinity it has highest electronegativity the highest electron affinity is for chlorine atom.
Last time i cheacked it could be Be
All electron shells represent an energy level - it doesn't matter if its the outermost shell or not. In order for there to be a release of energy the electron has to be coming from a higher energy state. The only energy state higher than the outer-most electron shell would be a free electron. The only way an electron becomes a free electron is that sufficient was provided to lift it from what-ever electron shell (energy level) it was previously in to escape velocity. The energy that it then releases in returning is then this exact same amount of energy.
The reason that the electron affinity is not as high as might otherwise be predicted for fluorine is that it is an extremely small atom, and so it's electron density is very high. Adding an additional electron is therefore not quite as favorable as for an element like chlorine where the electron density is slightly lower (due to electron-electron repulsion between the added electron and the other electrons in the electron cloud).
If you express your answer as a chemical equation with all forms given, you would get: Mg+(g) + e- -> Mg (g)
Yes. Non metals have larger electron affinity than metals as non metals accept electrons more easily than metals.
Last time i cheacked it could be Be
Fluorine gas is diamagnetic as there are no unpaired electrons A neutral atom of flurine would be paramagnetic as due to the presence of 1 unpaired electron in a 2p atomic orbital
It would be -1 because gaining an electron will create a negative charge. F has a high electron affinity and therefore becomes an F- ion quite readily.
Measure the equilibrium constant for the reaction of thermal electrons with a species at different temperatures. this has been done with an electron capture detector. another way to measure it is to make a negative ion and shine light on it and measure the energy of the electrons removed by this process Dr.Edward Chen
This element is rubidium.
All electron shells represent an energy level - it doesn't matter if its the outermost shell or not. In order for there to be a release of energy the electron has to be coming from a higher energy state. The only energy state higher than the outer-most electron shell would be a free electron. The only way an electron becomes a free electron is that sufficient was provided to lift it from what-ever electron shell (energy level) it was previously in to escape velocity. The energy that it then releases in returning is then this exact same amount of energy.
The reason that the electron affinity is not as high as might otherwise be predicted for fluorine is that it is an extremely small atom, and so it's electron density is very high. Adding an additional electron is therefore not quite as favorable as for an element like chlorine where the electron density is slightly lower (due to electron-electron repulsion between the added electron and the other electrons in the electron cloud).
If you express your answer as a chemical equation with all forms given, you would get: Mg+(g) + e- -> Mg (g)
The element with the greatest electronegativity in this scenario would be Cl or Chlorine.
Yes. Non metals have larger electron affinity than metals as non metals accept electrons more easily than metals.
which of these is an extensive property of a substance? is it color, hardness, malleability, or volume
when dealing with atomic chemistry in most cases a negative number indicate the gaining of at least one electron and a positive number indicate the loss of an electron. the definition of electron affinity in a nutshell is the ENERGY required to add an electron to in most cases the outermost shell, so the more electron you trying to add the higher the nergy and the more negative the number would be which would represent the amount of electron added eg.. if i want to add let say 2e- to a oxygen atom then the result would be O(g) + 2e- = O2-(g) also you can see that an anion is formed. on the other hand ionization energy is the somewhat the opposite, it is the removal of the most loosely held electron from a atom in the GASEOUS state forming cation in the end. eg.. Na(g) = Na+(g) + e- . Note that while ionization MUST be in the GASEOUS state electron affinity not necessarily have to. So dont used both terms as positive or negative loosely like that its just an indication of telling us what is going on whether the atom is loosing or gaining electron/s. hope this helps .