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Q: Why would one atom of oxygen want to bond with another one?
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Is oxygen a molecule or an atom?

oxygen is an element on the Periodic Table of elements. This means that oxygen is an atom which could bond with another element covalently to form a molecule


How does oxygen react with oxygen?

Oxygen is diatomic, meaning one oxygen atom will naturally bond with another to form O2.


A(n) bond results from the transfer of electrons from one atom to another atom?

That would be ... an ionic bond....


What type of bond does a silicon atom and oxygen atom have?

they will bond together with a double covalent bond


The covalent bond between a hydrogen atom and the oxygen atom in water is formed when?

The covalent bond between a hydrogen atom and and an oxygen atom when the two atoms share electrons. They form a water molecule when there are two hydrogen atoms sharing electrons with one oxygen atom.


Is Oxygen a covalent bond or a ionic bond?

Oxygen is an element. It forms chemical bonds with another oxygen atom, forming a nonpolar covalent bond. It forms covalent bonds with other nonmetals, and ionic bonds with metals.


What is a weak interaction involving a hydrogen atom and a fluorine oxygen or nitrogen atom?

That would be called a HYDROGEN BOND


What are two atoms that bond with a oxygen atom to form a water molecule?

two atoms that bond with a oxygen atom to form a water molecule


If two hydrogen atoms were fused would the fused atom still bond with an oxygen atom to create water?

yes


An bond is formed through a weak electrical attraction between a hydrogen atom bound to an electronegativeatom such as oxygen and nitrogen and another electronegative atom?

As long as the hydrogen is attached to Florine, oxygen, or nitrogen the bonding will be a hydrogen bond.


What can water molecules form hydrogen bonds with?

Water is composed of Two Hydrogen atoms that form a polar covalent bond with an oxygen atom.


What bond connects the hydrogen atom to the central oxygen atom of a water molecule?

A hydrogen bond.