Pair production can only occur if the energy of the photon is bigger than the rest mass (E0 = m0*c^2) of electron and positron, because this is the energy needed to create these particle (conservation of energy). Excess energy will be kinetic energy of the electron and positron. Rest mass of electron and positron is 0.511 MeV each, so 1.022 MeV in total.
1000 meters = 1kmTo get from meters to km you need to divide by 1000.So 1022 meters is the same as 1.022 km.
One MeV is one megaelectron volts or one million electron volts, and the MeV is a measure of energy. It is equal to 1.60217646 × 10-13 joules.
1022 add 1028 = 2050
None. Hydrogen and Helium are base elements.Helium is helium.Chemically yes, but with Nuclear Physics in stars:H + H --> D + e+ + v + 0.42 MeV, H + H --> D + e+ + v + 0.42 MeV, D + D --> He3 + n + 3.27 MeV (50%)H + H --> D + e+ + v + 0.42 MeV, H + H --> D + e+ + v + 0.42 MeV, D + D --> He3 + H + 4.03 MeV (50%)H + H --> D + e+ + v + 0.42 MeV, H + D --> He3 + gamma photon + 5.49 MeV, H + H --> D + e+ + v + 0.42 MeV, H + D --> He3 + gamma photon + 5.49 MeV, He3 + He3 --> He + H + H + 12.86 MeV (100%)H + D --> He3 + gamma photon + 5.49 MeV (100%)D + D --> He3 + n + 3.27 MeV (50%)D + D --> He3 + H + 4.03 MeV (50%)D + T --> He + n + 17.59 MeV (100%)T + T --> He + n + n + 11.33 MeV (100%)Four or two, depending on the kind of hydrogen isotope you are burning. As you can see in the equations above burning four ordinary atoms of hydrogen to ordinary helium is a complicated and slow process compared to burning two atoms of various isotopes of hydrogen, however a star has such tiny quantities of deuterium and tritium that depending on them for fusion helps little.
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one MeV has 1,000,000 eVs So one eV has 0.000001 MeVs
Cca. 200 MeV for 1 atom of uranium. (MeV = mega electronvolt = 106 eV).
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Muons decay by various methods, primarily, due to the weak interaction, into an electron and two neutrinos. The mass of the muon is 105.7 MeV/c2, with the mass of the electron being 0.511 MeV/c2, and the mass of the neutrino is less than 2.2 eV/c2. As a result, the loss of mass from muon decay, which is carried away as energy, is around 105.2 MeV/c2.
The MeV means million electron volts. It's a measure of the energy the energy in the photon, which is a quantum (or specific quantity) of electromagnetic energy. This 1 megaelectron volt = 1.60217646 × 10-13 joules of energy.
The photon energy of 1022 Hz is 4.22664452E-12 electron volts.
5,000,000