Yes. The reaction would be Ca + H2O --> Ca(OH)2 + H2. Hope that helped.
No, a reaction will not take place between calcium (Ca) and water (H2O). Calcium is a fairly unreactive metal and does not react with water at room temperature.
The balanced chemical equation for the reaction between calcium (Ca) and water (H2O) is: Ca + 2H2O -> Ca(OH)2 + H2. This reaction produces calcium hydroxide (Ca(OH)2) and hydrogen gas (H2).
The unbalanced chemical equation for the reaction of calcium metal with water is: Ca(s) + H2O(l) -> Ca(OH)2(aq) + H2(g).
The balanced equation for the reaction between calcium oxide and water is: CaO + H2O -> Ca(OH)2
The balanced equation for the reaction between calcium oxide (CaO) and water (H2O) is: CaO + H2O -> Ca(OH)2. This reaction produces calcium hydroxide (Ca(OH)2) as the product.
The balanced equation for this reaction is: Ca(OH)2 --> CaO + H2O.
yes if you mix anything with 2 hydrogen atoms and 1 oxagen atom than a reaction will take place
Ca + 2 H2O = Ca(OH)2 + H2
The word equation for the reaction between calcium oxide and water is: calcium oxide + water -> calcium hydroxide.
The reaction is: CaO(s) + H2O(l)--- --> Ca(OH)2(s) Ca(OH)2(s) is the product (at the right side of the reaction equation).
Ca(NO3)2 (s) + H2O (l) ===> Ca^2+(aq) + 2NO3^-(aq)
The reaction is:Ca + H2O = Ca(OH)2 + H2
The unbalanced chemical equation for the reaction of calcium metal with water is: Ca(s) + H2O(l) -> Ca(OH)2(aq) + H2(g).
The reaction is:Ca + 2 H2O = Ca(OH)2 + H2- hydrogen gas is released- the reaction occur at room temperature
Ca(OH)2 + 2 CH3COOH → Ca(CH3COO)2 + 2 H2O This is a double displacement reaction where calcium hydroxide neutralizes acetic acid to form calcium acetate and water. Balancing the equation involves ensuring that the number of atoms of each element are the same on both sides of the equation.
The reaction between hydrogen chloride gas (HCl) and lime water (Ca(OH)2) forms calcium chloride (CaCl2) and water (H2O). The balanced chemical equation is: 2HCl(g) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l).
The oxide ion in CaO (O2-) is a very strong base, meaning it will easily take a hydrogen ion (H+) from a molecule. In water the oxide ion take a hydrogen ion from a water molecule, forming to hydroxide ions. O2- + H2O --> 2OH- In this reaction the oxide ion acts as a base and the water molecule as an acid, at least by the Bronsted-Lowry definition.
To prepare chloroform from ethyl alcohol using the haloform reaction, you would first convert the ethyl alcohol to acetaldehyde by oxidizing it with an oxidizing agent like sodium hypochlorite. Then, treat the acetaldehyde with a strong base like sodium hydroxide to produce chloroform through a series of reactions involving halogenation and halide exchange. Finally, separate and purify the chloroform from the reaction mixture.