The reaction is:
Ca(OH)2 + 2 CH3COOH = Ca(CH3COO)2 + 2 H2O
1,1,1
You will need water for the reaction to take place. CO2(g)+H2O(l)--> H2CO3(aq) NOW IT IS BALANCED CaOH2(s)+H2CO3(aq) --> CaCO3(s)+2H2O(l)
Ca(OH)2 + Na2CO3 = CaCO3 + 2 NaOH
A white precipitate, that appears to be milky. Ca^2+(aq) + 2OH^-(aq) = Ca(OH)2 (s)
74.0932 g/mol
CaCl2 and H2O
Calcium Hydroxide, or CaOH2, is a base. Generally compounds containing hydroxyl groups and metals will act as bases in reaction.
1,1,1
You will need water for the reaction to take place. CO2(g)+H2O(l)--> H2CO3(aq) NOW IT IS BALANCED CaOH2(s)+H2CO3(aq) --> CaCO3(s)+2H2O(l)
Ca(OH)2 + Na2CO3 = CaCO3 + 2 NaOH
A white precipitate, that appears to be milky. Ca^2+(aq) + 2OH^-(aq) = Ca(OH)2 (s)
Nope... it is not.
74.0932 g/mol
NaOH+CaCO3
Calcium hydroxide.
Laboratory preparation of ammonia or NH3 requires using ammonium chloride and calcium hydroxide. The reaction equation is 2NH4Cl plus CaOH2 gives the products 2NH3 plus CaCl2 plus 2H2O. The ammonium chloride and calcium hydroxide are heated for this reaction.
Ca(OH)2(aq) + HNO3(aq) --> H2O(l) + Ca2+ (aq)+ NO3- (aq) Volume of Ca(OH)2 = 22.0mL = 0.022L Volume of HNO3 = 40.0 = 0.04L Molarity = moles of solute/Volume of solution M = .06/0.062 = 0.9677 M of Ca(OH)2