2hf + caoh2 = CaF2 + 2H2O
Acid is 'hf' ; hydrofluoric acid
Base is 'caoh2' ; calcium hydroxide.
NB
When writing chemcial formula , single letter symbols are ALWAYS a CAPITAL letter. Two letter symbols are always ; first letter is a capital letter and the secons letter is small case. This is the internationally agreed standard. Otherwise confusion reigns.
So 'hf' should be 'HF' (Hydrogen(H) and Fluorine(F)
'caoh"' should be 'Ca(OH)2' ( Calcium (Ca) , Oxygen (O) and Hydrogen (H)).
The suffix '2' indicates that there are two hydroxide anions, which are shown in brackets. As written by yourself 'caoh2' indicates 1 x calcium , 1 x oxygen and 2 x hydrogen.
Hope that helps for future reference!!!!
Rubidium hydroxide reacts with hydrofluoric acid to produce rubidium fluoride and water. The balanced chemical equation for this reaction is 2RbOH + 2HF -> 2RbF + 2H2O.
2KOH + H2SO4 --> K2SO4 + 2H2O2KOH(aq) + H2SO4(aq) --> K2SO4(aq) + 2H2O(l)
The balanced equation for Calcium Fluoride and sulfuric acid :- CaF2 + H2SO4 = Caso4 + 2HF
When hydrofluoric acid (HF) reacts with potassium hydroxide (KOH), they undergo a neutralization reaction to form potassium fluoride (KF) and water (H2O). The balanced chemical equation for this reaction is: 2HF + 2KOH -> 2KF + 2H2O. This reaction also releases heat due to the exothermic nature of the neutralization process.
To balance the chemical equation HF, you would need to place the coefficient "2" in front of HF. This would give you 2HF on both sides, creating a balanced equation: 2HF = 2HF.
Rubidium hydroxide reacts with hydrofluoric acid to produce rubidium fluoride and water. The balanced chemical equation for this reaction is 2RbOH + 2HF -> 2RbF + 2H2O.
2KOH + H2SO4 --> K2SO4 + 2H2O2KOH(aq) + H2SO4(aq) --> K2SO4(aq) + 2H2O(l)
The equation for the reaction between hydrofluoric acid (HF) and rubidium hydroxide (RbOH) is 2HF + 2RbOH → 2H2O + 2RbF, where water (H2O) and rubidium fluoride (RbF) are the products formed.
The balanced equation for Calcium Fluoride and sulfuric acid :- CaF2 + H2SO4 = Caso4 + 2HF
The balanced equation for the reaction of calcium carbonate (CaCO3) and hydrofluoric acid (HF) is: CaCO3 + 2HF → CaF2 + H2O + CO2.
When hydrofluoric acid solution is reacted with a lithium hydroxide solution, lithium fluoride and water are formed as products. The reaction can be represented by the following equation: 2HF(aq) + LiOH(aq) → LiF(aq) + 2H2O(l)
When hydrofluoric acid (HF) reacts with potassium hydroxide (KOH), they undergo a neutralization reaction to form potassium fluoride (KF) and water (H2O). The balanced chemical equation for this reaction is: 2HF + 2KOH -> 2KF + 2H2O. This reaction also releases heat due to the exothermic nature of the neutralization process.
The double replacement reaction between potassium fluoride and hydrobromic acid would result in the formation of potassium bromide and hydrofluoric acid. The balanced chemical equation for this reaction is: 2KF + 2HBr → 2KBr + 2HF.
To balance the chemical equation HF, you would need to place the coefficient "2" in front of HF. This would give you 2HF on both sides, creating a balanced equation: 2HF = 2HF.
Hydrogen fluoride (HF) . It will dissolve in water to form 'hydrofluoric acid' H2(g) + F2(g) = 2HF(g)
Answer this question…Mixing sodium hydroxide with hydrochloric acid to form table salt and water
I don't know whether or not this reaction actually happens, but if it does, this is what would be produced. Al + BaO --> Al2O3 + Ba The balanced equation is as follows: 2Al + 3BaO --> Al2O3 + 3Ba