answersLogoWhite

0

Definitely not possible. Capacitance is given by an expression

C = epsilon x A / d

Since charge is not present the capacitance cannot be increased or decreased by the charge placed

User Avatar

Wiki User

12y ago

What else can I help you with?

Continue Learning about Physics

Two charges are separated by a distance d If one the charges is doubled while the other is tripled what happens to the force between the charges?

We have to assume that the distance between the charges remains constant, and the answer doesn't depend on the distance. The force between the charges is proportional to the product of the charges. Initial force = constant x (Q1) x (Q2) New force = constant x (2Q1) x (3Q2) = 6 x (Q1) x (Q2) = 6 times the initial force. The direction of the force doesn't change. It's attractive if the charges are of opposite sign, repulsive if they're of like sign.


If the distance is increased while the charges remain the same what happens to the force?

If the distance between charges is increased while the charges remain the same, the force between the charges decreases. This relationship is described by Coulomb's law, which states that the force between charges is inversely proportional to the square of the distance between them.


How does the electric force between two charged particles charge is increased by a factor of 2?

By increasing the distance between them by sqrt(2).


How does the electric potential energy between two charged particles change if one particles charge is increased by a factor of two?

It is increased by a factor of 2


How does the electric potential energy between two charged particles change if one particle's charge is increased by a factor of 2?

The electric potential energy between two charged particles is directly proportional to the product of their charges. If one particle's charge is increased by a factor of 2, the potential energy between the two particles will increase by a factor of 2 as well.

Related Questions

If the two charges are fixed such that the distance r is between them does not change but the charge q is increased will the electric force become stronger or weaker?

If the charges increase, the force increases.If the charges increase, the force increases.If the charges increase, the force increases.If the charges increase, the force increases.


Increase in resonance structure leads to increase in stabilitywhy?

Increasing the number of resonance structures increases the delocalization of electrons, spreading the positive and negative charges over a larger area. This increased delocalization results in lower overall energy and increased stability of the molecule.


If your horse frequently exercises wich do you feed them increase protein increase carboyhdrates increase fat and increase glucose?

Increased Protein and increased carboyhydrates.


Why increase in selling price doesnt increase profit?

It is simple that if the selling price is increased more then of cost increase then profit will increase but if selling price increased less then cost increased then there will be less profit or selling price increased in same proportion to cost increased then there may be no increase in profit. Besides that there may be so many other reasons for that.


In a closed circuit what does an increase in voltage cause?

an increase in current, hence increased power and increased heat.


If 8 is increased to 11 the increase is what percent of the original number?

If 8 is increased to 12, the increase is what percentage of the original number?


What is force-current analogy mass is analogous to?

in FV analogy, mass is analogous to inductance


Two charges are separated by a distance d If one the charges is doubled while the other is tripled what happens to the force between the charges?

We have to assume that the distance between the charges remains constant, and the answer doesn't depend on the distance. The force between the charges is proportional to the product of the charges. Initial force = constant x (Q1) x (Q2) New force = constant x (2Q1) x (3Q2) = 6 x (Q1) x (Q2) = 6 times the initial force. The direction of the force doesn't change. It's attractive if the charges are of opposite sign, repulsive if they're of like sign.


If the distance is increased while the charges remain the same what happens to the force?

If the distance between charges is increased while the charges remain the same, the force between the charges decreases. This relationship is described by Coulomb's law, which states that the force between charges is inversely proportional to the square of the distance between them.


What is the past tense of increase?

The past tense of increase is increased.


If 5.59 is increased to 6.09 what is the percent increase?

8.94% increase.


What is 65 increased to 144?

It is an increase of 79, which is an increase of about 121.54%.