We have to assume that the distance between the charges remains constant, and the answer doesn't depend on the distance. The force between the charges is proportional to the product of the charges. Initial force = constant x (Q1) x (Q2) New force = constant x (2Q1) x (3Q2) = 6 x (Q1) x (Q2) = 6 times the initial force. The direction of the force doesn't change. It's attractive if the charges are of opposite sign, repulsive if they're of like sign.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased
Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times
Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
When the distance between the centers of two objects is doubled, the gravitational forces between the objects are reduced by 75% .
The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .
The force between the two charges increases 16 times.Coulomb's law equation states:│F│ = ke │q1q2│/r2Where (F) is the force acting simultaneously on both point charges (q1) and (q2).r is the separation distance and ke is a proportionality constant called the Coulombconstant.Using above equation, if we double both charges and reduce the distance in half.│F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.We see that the force turns out 16 times stronger
If one of the two masses doubles but the distance between them remains unchanged,then the magnitude of the gravitational force between them is also doubled.
Doubled
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
If the magnitude of each of two charges is doubled, then the direction of the force between them doesn't change, but its magnitude increases by a factor of 4.
When the distance between the centers of two objects is doubled, the gravitational forces between the objects are reduced by 75% .
The electric force will be quarter of its strength.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .
The force between the two charges increases 16 times.Coulomb's law equation states:│F│ = ke │q1q2│/r2Where (F) is the force acting simultaneously on both point charges (q1) and (q2).r is the separation distance and ke is a proportionality constant called the Coulombconstant.Using above equation, if we double both charges and reduce the distance in half.│F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.We see that the force turns out 16 times stronger
If one of the two masses doubles but the distance between them remains unchanged,then the magnitude of the gravitational force between them is also doubled.
I dont know haha you tell me.
It should fall to a quarter.
Electric force can act at a distance, but is stronger when objects are closer. the electric force is larger the closer the two objects are The electric force varies with the distance between the charges. The closer they are, the stronger the force. The farther apart they are, the weaker the force.