The force between the two charges increases 16 times.
Coulomb's law equation states:
│F│ = ke │q1q2│/r2
Where (F) is the force acting simultaneously on both point charges (q1) and (q2).
r is the separation distance and ke is a proportionality constant called the Coulomb
constant.
Using above equation, if we double both charges and reduce the distance in half.
│F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.
We see that the force turns out 16 times stronger
The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
If one of the two masses doubles but the distance between them remains unchanged,then the magnitude of the gravitational force between them is also doubled.
Whatever be the magnitude of charge, two charges will always exert equal force on each other. As force depends on the product of magnitude of charges, it will increase if magnitude is doubled but will remain same for both the charges.
When the distance between the centers of two objects is doubled, the gravitational forces between the objects are reduced by 75% .
If the magnitude of each of two charges is doubled, then the direction of the force between them doesn't change, but its magnitude increases by a factor of 4.
I dont know haha you tell me.
The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
If one of the two masses doubles but the distance between them remains unchanged,then the magnitude of the gravitational force between them is also doubled.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
Whatever be the magnitude of charge, two charges will always exert equal force on each other. As force depends on the product of magnitude of charges, it will increase if magnitude is doubled but will remain same for both the charges.
Doubled
When the distance between the centers of two objects is doubled, the gravitational forces between the objects are reduced by 75% .
I am not sure but i thinks they are:Positive chargeNegative charge
Since, F = 9 x 109 q1q2/r2 provided force between two charges = 1NWhen the magnitude of each charge is double then F' = 9 x 109 (2q1)(2q2)/(2r)2 = FThe force on the charge will remain unchanged.
It should fall to a quarter.