Three kings and two nines is a full house, three aces is a three of a kind. A full house always beats a three of a kind.
yes
Three aces and two eights is a full house. Three Aces and two nines would win. As would three aces and two kickers 10 or higher.
Yes 3 of a kind always beats two pair.
No.
In High Card Poker, the hand with the highest ranking combination wins. A hand of three Aces, a 2, and a 4 (three of a kind) beats a hand with a pair of Kings, a pair of Queens, and a 5 (two pair). Therefore, the three Aces hand wins.
Yes always. e.g. three sevens (777) beats a pair of kings and a pair of aces (KKAA)
In poker, a hand is ranked primarily by its highest combination. A pair of aces and a pair of sixes (two pair) beats a pair of kings and a pair of tens (also two pair) because aces are the highest-ranking cards. Therefore, the hand with aces and sixes wins.
Three aces in poker does not beat a small straight. A small straight beats three of a kind and two of a kind.
Two pair works like this, the higher pair determines who is the winner. Suppose I have two pair Aces and fives, that means I beat all two pair that have kings as the higher pair, and queens etc. So Aces and fives beats Kings and queens. Now, if there is tie then the second pair comes in, so Aces and fives loses to Aces and sevens.
No. A full house (888KK) always beats three of a kind (KKK).
In poker, three of a kind (three kings) does not beat a straight. A straight, which consists of five consecutive cards of any suit, ranks higher than three of a kind. Therefore, if one player has three kings and another has a straight, the player with the straight wins the hand.
The pair of queens beat the pair of tens, the nine and the ace are irrelevant. Queens are higher ranked than tens.