answersLogoWhite

0


Best Answer

LiBr is an ionic compound.

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Would LiBr be classified as ionic or covalent?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Is LlBr covalent or ionic?

LiBr lithium bromide is ionic, consisting of Li+ and Br- ions


What type of chemical bond is LiBr?

Ionic. lithium has a charge of plus one, bromine has a charge of negative one.


Is LiBr a ionic solid?

Yes, LiBr is an ionic solid.


Is LiBr ionic or molecule?

Lithium bromide (LiBr) is a chemical compound.


Is LiBr a covalent bond?

NO!!! It is an Ionic bond, similar to sodium chloride.


What is the name of formula LiBr?

LiBr= Lithium bromide==================an ionic compound


Which of the following is connected by an ionic bond IC LiBr HCL?

Lithium bromide is an ionic compound.


Is LiBr ionic or covalent?

Yes, LiCl is the chemical formula for the compound lithium chloride. It is an ionic compound, where there is strong electrostatic attraction between oppositely charged Li+ and Cl- ions. The lithium and chloride ions occupy alternate and opposite positions in the giant lattice structure characteristic of an ionic compound.


How do you draw the ionic compound LiBr?

That would be: Li+ bonded via the 'Shared Electron Pair' with Br-; or Li+Br-. Linus Pauling was the originator of the Shared Electron Pair concept!


What is the name for the ionic compound for Li Br?

Lithium bromide, LiBr, is prepared by the treatment of lithium carbonate with hydrobromic acid


What is the classification of Lithium?

Lithium bromide is an inorganic compound, an ionic salt. Formula: LiBr Solubility in water: Soluble Appearance: White solid


Why does LiBr have a higher boiling point than I2?

LiBr is a salt and part of a crystal lattice. The bonding is thus very strong requiring a lot of energy to break them resulting in a fairly high melting point like NaCl. Iodine I2 has a much weaker single covalent bond.