LiBr
= Lithium bromide
==================an ionic compound
Lithium Bromide
lithium bromide
Lithium Bromine
Lithium Bromide = LiBr
Not atoms of LiBr; formula units is correct.1 mol = 6,022 140 857.10e23 (molecules, atoms, ions); this is the Avogadro number.6,022 140 857.10e23 x 1,25 = 7,52767607125.10e23 formula units of LiBr
The symbol for a bromide ion is Br-.
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
Lithium Bromine
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
Lithium bromide is LiBr
Lithium Bromide = LiBr
Not atoms of LiBr; formula units is correct.1 mol = 6,022 140 857.10e23 (molecules, atoms, ions); this is the Avogadro number.6,022 140 857.10e23 x 1,25 = 7,52767607125.10e23 formula units of LiBr
Lithium Bromide
The symbol for a bromide ion is Br-.
Lithium Bromine
Becuase that is what they decided to name it.
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
Yes, LiBr is an ionic solid.
Lithium bromide (LiBr) is a chemical compound.