0
How many atoms of LiBr would you have if you start with 1.25 moles What is the answer and how did you get it?
LOLZlilly20911
Not atoms of LiBr; formula units is correct.
1 mol = 6,022 140 857.10e23 (molecules, atoms, ions); this is the Avogadro number.
6,022 140 857.10e23 x 1,25 = 7,52767607125.10e23 formula units of LiBr
Wiki User
∙ 6y ago
Add your answer:
Earn +20 pts
When 7.6 grams of LiBr is dissolved how many moles of cation are produced?
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088
Would LiBr be classified as ionic or covalent?
LiBr is an ionic compound.
What is the mass in grams of 3.50mol LiBr?
step 1: calculate the molar mass of one molecule LiBr by adding together their amu (atomic mass units) step 2: 3.50 mol * ( molecular mass LiBr / 1 mol LiBr ) = grams LiBr amu on your periodic table is grams when you have one mol of that substance
Is LiBr a ionic solid?
Yes, LiBr is an ionic solid.
Lithium hydroxide reacts with hydrobromic acid to produce lithium bromide and water If you start with then grams of lithium hydroxide how many grams of lithium bromide will be produced?
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
How many atoms are found in 10 moles of LiBr?
10 moles LiBr (6.022 X 1023/1 mole LiBr)= 6.022 X 1024 atoms of lithium bromide=========================
When 7.61 grams of LiBr is dissolved how many moles of anion are produced?
7,61 g LiBr contain 6,99 g Br.6,99 g Br is 0,087 moles.
The formula for lithium bromide is?
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
When 7.6 grams of LiBr is dissolved how many moles of cation are produced?
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088
Would LiBr be classified as ionic or covalent?
LiBr is an ionic compound.
1 Lithium reacts spontaneously with Bromine to produce Lithium bromide Write the balanced chemical equation for the reaction If 25.0 g of Lithium and 25.0 g of Bromine are present at the beginning?
2 Li + Br2 = 2 LiBr is the balanced reaction eq'n. For the second part you need to calculate the moles. moles(Li) = 25 / 7 = 3.57 moles(Br2) = 25 / )80 x 2) = 0.15 BY mathematical equivalence of the reaction eq'n 2:1::2 = 0.3:0.15 :: 0.3 So only 0.3 moles (LI) will be reacted, leaving ( 3.57 - 0.3 = 3.27 moles) unreacted. ( That 22.85 g lithium unreacted) It will give a product mass of 7.2 g (LiBr)
What is the mass in grams of 3.50mol LiBr?
step 1: calculate the molar mass of one molecule LiBr by adding together their amu (atomic mass units) step 2: 3.50 mol * ( molecular mass LiBr / 1 mol LiBr ) = grams LiBr amu on your periodic table is grams when you have one mol of that substance
Is LiBr a ionic solid?
Yes, LiBr is an ionic solid.
Is LiBr ionic or molecule?
Lithium bromide (LiBr) is a chemical compound.
Lithium hydroxide reacts with hydrobromic acid to produce lithium bromide and water If you start with then grams of lithium hydroxide how many grams of lithium bromide will be produced?
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
How many moles of lithium chloride will be formed by the reaction of chlorine with 046 moles of lithium bromide in the following reaction 2 LiBr plus Cl2 equals 2 LiCI plus Br2?
2LiBr(aq) + Cl2(g) = 2LiCl(aq) + Br2(l) will result in .167 moles of lithium chloride.
What is the percent of composition for LiBr?
LiBr contain 8,139 % lithium and 91,860 % bromine.
