0
step 1: calculate the molar mass of one molecule LiBr by adding together their amu (Atomic Mass units)
step 2: 3.50 mol * ( molecular mass LiBr / 1 mol LiBr ) = grams LiBr
amu on your Periodic Table is grams when you have one mol of that substance
What else can I help you with?
Lithium hydroxide reacts with hydrobromic acid to produce lithium bromide and water If you start with then grams of lithium hydroxide how many grams of lithium bromide will be produced?
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
What is the percent composition of lithium in LiBr?
The percent composition of lithium in LiBr is approximately 7.0%. This is calculated by dividing the molar mass of lithium by the molar mass of LiBr and then multiplying by 100.
What is the percent of composition for LiBr?
LiBr contain 8,139 % lithium and 91,860 % bromine.
When 7.6 grams of LiBr is dissolved how many moles of cation are produced?
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088
How many atoms of LiBr would you have if you start with 1.25 moles What is the answer and how did you get it?
Not atoms of LiBr; formula units is correct.1 mol = 6,022 140 857.10e23 (molecules, atoms, ions); this is the Avogadro number.6,022 140 857.10e23 x 1,25 = 7,52767607125.10e23 formula units of LiBr
Lithium hydroxide reacts with hydrobromic acid to produce lithium bromide and water If you start with then grams of lithium hydroxide how many grams of lithium bromide will be produced?
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
The formula for lithium bromide is?
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
What is the percent composition of lithium in LiBr?
The percent composition of lithium in LiBr is approximately 7.0%. This is calculated by dividing the molar mass of lithium by the molar mass of LiBr and then multiplying by 100.
What is the percent of composition for LiBr?
LiBr contain 8,139 % lithium and 91,860 % bromine.
When 7.6 grams of LiBr is dissolved how many moles of cation are produced?
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088
When 7.61 grams of LiBr is dissolved how many moles of anion are produced?
7,61 g LiBr contain 6,99 g Br.6,99 g Br is 0,087 moles.
What is the mass in atoms of 350 mol of bromine?
To find the mass of 350 mol of bromine, you need to multiply the number of moles by the molar mass of bromine. The molar mass of bromine is approximately 79.9 g/mol. So, 350 mol * 79.9 g/mol = 27965 g. Therefore, the mass of 350 mol of bromine is 27965 grams.
How many atoms of LiBr would you have if you start with 1.25 moles What is the answer and how did you get it?
Not atoms of LiBr; formula units is correct.1 mol = 6,022 140 857.10e23 (molecules, atoms, ions); this is the Avogadro number.6,022 140 857.10e23 x 1,25 = 7,52767607125.10e23 formula units of LiBr
What is the mass of 60 grams 0 grams and 2.2 grams?
The mass of 60 grams is 60 grams, the mass of 0 grams is 0 grams, and the mass of 2.2 grams is 2.2 grams.
Is libr soluble or insoluble in water?
Libr is soluble in water.
What is the symbol of cation of LiBr?
Lithium bromide (LiBr) is a compound, not a cation. The cation is Li+.
If the mass of the container is 14.5 grams what is the mass of the sand?
To determine the mass of the sand, you'll need to subtract the mass of the container (14.5 grams) from the total mass of the container with sand in it. For example, if the total mass of the container with sand is 50 grams, then the mass of the sand would be 50 grams - 14.5 grams = 35.5 grams.
