step 1: calculate the molar mass of one molecule LiBr by adding together their amu (Atomic Mass units)
step 2: 3.50 mol * ( molecular mass LiBr / 1 mol LiBr ) = grams LiBr
amu on your Periodic Table is grams when you have one mol of that substance
3.40 X 1022 atoms helium (1 mole He/6.022 X 1023)(4.003 grams/1 mole He)
= 0.226 grams of helium
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4.32x10(-2)g Li
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088
Yes, LiBr is an ionic solid.
LiBr is an ionic compound.
LiBr contain 8,139 % lithium and 91,860 % bromine.
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
1 mol of bromine has 79.904g. 79.904g/mol x 350mol =
7,61 g LiBr contain 6,99 g Br.6,99 g Br is 0,087 moles.
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088
Yes, LiBr is an ionic solid.
Lithium bromide (LiBr) is a chemical compound.
LiBr is an ionic compound.
LiBr contain 8,139 % lithium and 91,860 % bromine.
LiBr contain 8,139 % lithium and 91,860 % bromine.
Grams are a measure of mass.
Lithium bromide (LiBr) is a compound, not a cation. The cation is Li+.