Oxygen will gain two electrons to achieve a full outer shell.
Oxygen needs to gain two electrons to achieve a stable electron configuration, which would give it a full outer shell of eight electrons (octet). This can be achieved through forming chemical bonds with other elements.
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Bromine will gain one electron when forming an ion to achieve a full outer electron shell. This will give it a stable electron configuration.
Oxygen gains 2 electrons when forming an ion. This is because oxygen typically forms an anion by gaining 2 electrons to achieve a stable, full outer electron shell similar to the nearest noble gas configuration.
Nitrogen gains 3 electrons, oxygen gains 2 electrons, sulfur gains 2 electrons, and bromine gains 1 electron when forming ions.
Sulfur can both gain and lose electrons when forming ions. It can gain two electrons to form a sulfide ion (S2-) or lose two electrons to form a sulfide ion (S2+).
Yes, if a chlorine atom attracts an electron from sodium, the chlorine atom would gain an extra electron and become negatively charged, forming a chloride ion (Cl-). Sodium, on the other hand, would lose an electron and become positively charged, forming a sodium ion (Na+).
Lithium has one valence electron. It is much easier for an atom to lose one electron than gain seven more. Lithium looses this one electron to achieve a full outer shell (the next inside shell is full).
Bromine typically gains one electron when forming an ion to achieve a stable electron configuration. The electron configuration for a bromine ion is [Kr] 4d10 5s2 5p6, which is the same as that of a noble gas.
Bromine is most likely to gain one electron when forming an ion, as it is in Group 17 of the periodic table (halogens) with 7 valence electrons. By gaining one electron, bromine achieves a stable octet and forms a Br- ion.
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