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public class LeapYear {
public static void main(String[] args) {
int year = Integer.parseInt(args[0]);
boolean isLeapYear;
// divisible by 4
isLeapYear = (year % 4 == 0);
// divisible by 4 and not 100
isLeapYear = isLeapYear && (year % 100 != 0);
// divisible by 4 and not 100 unless divisible by 400
isLeapYear = isLeapYear (year % 400 == 0);
System.out.println(isLeapYear);
}
}
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∙ 14y ago
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How do you write a program in java to check a year leap year or not and display the proper message?
You can use a number of nested "if" commands. The rules are the following: If the year is a multiple of 400, it IS a leap year. Else, if the year is a multiple of 100, it's NOT a leap year. Else, if the year is a multiple of 4, it IS a leap year. Else it's NOT a leap year. In Java, to check for divisibility, you use the "%" operator, which gives you the remainder of a division. For example: if (year % 400 = 0) ... To show results on screen, you use: System.out.println(...)
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Write a program to check whether a given year is leap year or not using ternary operator?
leap yr = ((y%100!=0 && yr %400==0)?1:(yr%4==0)?1:0; leap yr =1; printf ("leap yr"); else printf ("not leap yr");
How do you find leap year?
Find the modulo of the year by 4. If the value is 0,then it is a leap year. Otherwise it is not a leap year.
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the Great Leap Forwardthe Great Leap Forward
Write a c program to find leep year through nested if?
// leap year by @bhi// #include<stdio.h> #include<conio.h> void main() { int year; clrscr(); printf("Enter the Year that you want to check : "); scanf("%d", &year); if(year % 400 == 0) printf("%d is a Leap Year.", year); else if(year % 100 == 0) printf("%d is not a Leap Year.", year); else if(year % 4 == 0) printf("%d is a Leap Year.", year); else printf("%d is not a Leap Year", year); printf("\nPress any key to Quit..."); getch(); }
C program to find the year is leap year or not?
Algorithm: If the year is not divisible by 4 then it is not a leap year. Else if the year is not divisible by 100 then it is a leap year. Else if the year is not divisible by 400 then is not a leap year. Else it is a leap year. Implementation: bool is_leap_year (unsigned year) { if (year%4) return false; if (year%100) return true; if (year%400) return false; return true; }
'write a program to check whether given year is a leap year or not?
#include using namespace std;int main(){short numberOfDays = 0;cout > numberOfDays;if (numberOfDays == 365){cout
What is the program in c to check whether a year is leap year or not in simple way?
If the year divides evenly by 4 it's a leap year. If it's a century year it has to divide evenly by 400. 2000 was a leap year. 2100 will not be a leap year.
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Umbrae saliunt
