Zr2+ => [Kr] 5s0 4d2, it may vary to: [Kr] 5s2 4d0 or in between: [Kr] 5s1 4d1
Added:
It's hard to draw arrows on this 'chart' with poor layout properties, so a \ will be an arrow going one way (up) and a / will be the other way (down). A [ ] represents a box. (Ignore the , they're just place holders)
[ ] , [ \ ] [ \ ] [ ] [ ] [ ]
5s0, 4d2
[\ /], [ ] [ ] [ ] [ ] [ ]
5s2, 4d0
[ \ ], [ \ ] [ ] [ ] [ ] [ ]
5s1, 4d1
Zr with a 2+ indicates that there are two fewer electrons present. This makes the electron shell diagram begin with the base of [Kr], with an outer shell of 5s2.
There is really nothing to diagram. Magnesium plus oxygen becomes magnesium oxide plus energy.
It has 39 electrons and ends in a d orbital. Now finish your homework :)
CO+ has a shorter bond length than CO- so its bond order is greater! As student yoyu are prbably expecte to use an MO diagram removing an electron from the HOMO highest occupied molecular orbital. there are different diagrams around. Some of them indicate that bond order will increase as you are removing an electron from an anti-bonding orbital a 2s-sigma. You may wish to look at the digram that your teacher has recommended and use that to get the "right" answer - the test is how to use MO diagrams after all.
because in aqueous state copper has minimum hydration enthalpy in an oxidation state of +2, so it is most stable in +2 oxidation state
6c2h6+21o2=12co2+18h2o
Yes, this is possible.
There are 5 electrons in the d orbital of an Os3+ ion.
With the aid of a diagram,illustrate how the c plus plus compiler works?
I+++?
There is really nothing to diagram. Magnesium plus oxygen becomes magnesium oxide plus energy.
How do you write 100,000 plus 20,000 plus 1,000 plus 900 plus 30 plus 9?
splendor plus engine diagram
You write it as 3,072,856
It has 39 electrons and ends in a d orbital. Now finish your homework :)
Yes, it is. If we look at the electronic configuration of Mn2+ , it is 1s2 2s2 2p6 3s2 3p6 4s0 3d5 . The 3d orbital is half-filled, which is relatively stable. in Mn3+ , there are only 4 electrons in the 3d orbital, which is less stable.
800,040,960
8.059