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X2 - 12x 36

Updated: 4/28/2022
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11y ago

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x2 - 12x + 36 = (x - 6)2

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X2 - 12x plus 36?

x2-12x+36 = (x-6)2


X2 plus 12x plus 36 equals 0?

x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7


X2 plus 12x-6 equals 0?

If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42


Factor X2-12x plus 36 equals 0?

=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0


X2-12x plus 36 equals 11?

x=5/2*sqr(3)


What is the factorization of the trinomial -x2 plus 12x plus 28?

x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored


How can you rewrite equation x squared plus 12x plus 5 equals 3?

x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0


What is x squared plus 12x plus 36 equals?

Equate it to zero (0) , and you have a quadratic equation that can be factotred. Hence x^2 + 12x + 36 = 0 (x + 6)(x + 6) = 0 Hence x = -6


What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?

Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.


How do you Factor the following polynomial 6x2plus72xplus216?

6.(x2 + 12x + 36) = 6.(x + 6)(x + 6)


What are the Factors of X2 12x 36?

Assuming the missing signs are pluses, that factors to (x + 6)(x + 6)


What is the answer to completing the square to x2 plus 12x-11?

x2 + 12x - 11 = x2 + 12x + (12/2)2 - (12/2)2 - 11 = (x + 6)2 - 47