X = 10
II = 2
and VII = 7
I, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, X
I, II, III, IV, V, VI, VII, VIII, IX, X or i, ii, iii, iv, v, vi, vii, viii, ix, x
They are I II III IV V VI VII VIII IX and X.(in some, non-subtractive, forms, I II III IIII V VI VII VIII VIIII X
I, II, III, IV, V, VI, VII, VIII, IX, X, XI and XIII, ii, iii, iv, v, vi, vii, viii, ix, x, xi ,xii
They are: I, II, III, IV, V, VI, VII, VIII, IX, X, XI and XIII, ii, iii, iv, v, vi, vii, viii, ix, x, xi, xii
Vii 1 = i 2 = ii 3 = iii 4 = iv 5 = v 6 = vii 8 = viii 9 = ix 10 = x
The answer is 174.DXXII/III = (C + LX + VI + II/III) + (III + I/III) + (III + I/III) + II/III = CLXXIVDXXII/III == D/III + X/III + X/III + II/III == (CxV)/III + (III + I/III) + (III + I/III) + II/III == Cx(V/III) + VII + I/III == Cx(I + II/III) + VII + I/III == C + (CxII)/III + VII + I/III == C + ((XxX)xII)/III + VII + I/III == C + Xx(XxII)/III + VII + I/III == C + Xx(VI + II/III) + VII + I/III == C + LX + (XxII)/III + VII + I/III == C + LX + VI + II/III + VII + I/III == CLXXIV
Mainly the popes Julius II, Leo X, Clement VII and Paul III.
I,II,III,IV,V,VI,VII,VIII,IX,X
I, ii, iii, iv, v, vi, vii, viii, ix, x
XVII
The Roman numeral symbols for 1 to 12 are I, II, III, IV, V, VI, VII, VIII, IX, X, XI, and XII.