x= 19 x + (x-5)= 33 x + x= 33+5 2x=38 x=38/2 x=19
X=-33
33
x+33=999 x=999-33=966
x=3 actually its 7
5+5x5=30 but (5+5)x5=50
x + 2x = 33 3x = 33 3x/3 = 33/3 x = 11
x = 59
8x + 33 = 7x + 27 Subtract 7x from both sides: x + 33 = 27 Subtract 33 from both sides: x = -6
1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x
This is related to an x + (x+1) + (x+2) function, in which case x equals 10. 10+11+12 is equal to 33.
8x + 11 = 33 + 6x 8x - 6x = 33 - 11 2x = 22 x = 11
Since x and y are variables, the sum of 5x and 5y could be literally any number.