y = 16 - x
Add 'x' to each side:
x + y = 16
Subtract 'y' from each side:
x = 16 - y
Y=(x+8)^2-5
.25
No. A proportional relationship between "y" and "x" must be of the form:y = kx where "k" can be any constant. Thus, y = 16x would work perfectly. However, the additional "+4" makes it impossible to convert it to this form.
16 + x = y
Ok, in order for anyone to give you the common factor of this, we need the format. is this -16x^2? If so, then the common factor would be x. x is the only thing that -16x^2, 1000x, and x have in common. If this were -16x^2 + 1000x + x =y then it would simplify to x(-16x+1001)=y. Ok, in order for anyone to give you the common factor of this, we need the format. is this -16x^2? If so, then the common factor would be x. x is the only thing that -16x^2, 1000x, and x have in common. If this were -16x^2 + 1000x + x =y then it would simplify to x(-16x+1001)=y.
If: 16x-15-6x = 13 Then: 10x = 28 And: x = 2.8.
x=2.52
16x = 4 Divide both sides by 16: x = 4/16 x = 1/4
7.5625
-29
If your function is 4x^2+16x+16=0 then x=-2, if it is 4x^2-16x+16=0, then x=2
16x+y