Only if all the suits are the same for the 9 10 Q Q K combo and all the suits are not the same on the 9 9 8 8 K combo - in that case, you'd have a straight. Otherwise, no - 9 10 Q Q K is only one pair, whereas 9 9 8 8 K is two pair.
The probability is 1. And the same is true for any other digit.This counter-intuitive result can be proved as follows:Ignore numbers with leading zeros.There are 9 1-digit numbers of which 8 do not contain any 2s;There are 90 2-digit numbers of which 8*9 do not contain any 2s;There are 900 3-digit numbers of which 8*9*9 do not contain any 2s;and so on.The total number of k digit numbers is 9 + 90 + 900 + ... + 9*10^(k-1)= 9*[10^k-1]/[10 - 1] = 10^k - 1Of these, the count of numbers which do not contain any 2s = 8 + 8*9 + 8*9^2 + ... + 8*9^(k-1)= 8*[9^k-1]/[9 - 1] = 9^k - 1So the probability that the numbers do not contain any 2s is [9^k - 1]/[10^k - 1] which, as k gets larger, approaches 9^k/10^k = (0.9)^k which tends to 0.So, the probability that the number DOES contain at least one 2 = 1 - Pr(It contains none) = 1 - 0 = 1.
red Q, red Q, black Q, black Q, J, 6, 7, 3, K, 2, 5, 2, 5, J, 7, K, 6, 7, 3, K, 6, 7, 3, K, 2, 5, 10, 10, 10, 10, J, 4, 4, 8, 8, 8, 4, 9, 9, 9, 9, 8, A, A, A, A, "What The Hell", J, 2, 3, 4, 5, 6 (2-6 need to be spades)
It is a fraction of the form (8*k)/(9*k) where k is any non-zero integer.
In poker, a straight is a hand that consists of five consecutive cards of any suit. The possible straights in poker are: A-2-3-4-5 (also known as a wheel or bicycle) 2-3-4-5-6 3-4-5-6-7 4-5-6-7-8 5-6-7-8-9 6-7-8-9-10 7-8-9-10-J 8-9-10-J-Q 9-10-J-Q-K 10-J-Q-K-A These are the ten possible straights in poker, with the highest being a 10-J-Q-K-A straight.
(k+3)/8 = 5/9 Cross Multiply: 9(k+3) = 5*8 Distribute: 9k+27 = 40 Subtract 27 from each side: 9k = 13 Divide each side by 9: k = 13/9
K so to betaBxnxjdnsneke
where k = 1/4(pi)Eo = 9*10^9 (approx) Fc/k = Q1*Q2 / r^2 = (1.6*10^-19c)^2 / (5*10^-8)^2 = 1.024*10^-23 = Fc/k therefore Fc = (1.024*10^-23).(9*10^9) = 9.216*10^-14N hopfully someone will jump in if im wrong.
They are members of the infinite set of numbers of the form 360*k where k is an integer. Since the set is infinite, it is not possible to list them.
When you divide a number by 9 and the remainder is 8, it means that the number can be expressed in the form ( n = 9k + 8 ), where ( k ) is an integer. This means the number is 8 more than a multiple of 9. For example, if ( k = 0 ), the number is 8; if ( k = 1 ), the number is 17; and so on. Thus, any number of this form will have a remainder of 8 when divided by 9.
It is (k*5)/(k*8) for any non-zero integer k.
2x+5y=8 8-2x=5y y=-0.4x+1.6 for y=mx+c, m is the gradient, -2/5. The perpendicular line will have a gradient of a negative reciprocal of the first, so 5/2 or 2.5. kx-4y=9 kx-9=4y y=(k/4)x-2.25 as such, k/4=2.5 k=10
It is 2 + 24*k hours where k is an integer.