A sodium atom has one valence electron.
The order is: Iodine (7 valence electrons) Carbon (4 valence electrons) Calcium (2 valence electrons) Sodium (1 valence electron)
Sodium ion (Na+) has 10 valence electrons and oxygen ion (O2-) has 8 valence electrons.
There are a total of 11 electrons in Sodium.
Sodium's atomic number is 11. To be neutral then, it must have 11 protons and 11 electrons. Since sodium is in group 1, it has 1 valence electron.
the number of protons is the atomic number, which for sodium is 11. The number of electrons in neutral sodium atom is 11 and these are in the following shells:- 1st valence = 2 electron 2nd valence = 8 electrons 3th valence = 1 electrons
Sodium has one valence electron.
Silicon has 4 Calcium has 2 Chlorine has 7 Sodium has 1
Sodium iodide (NaI) consists of sodium (Na) and iodine (I) atoms. Sodium has 1 valence electron, while iodine has 7 valence electrons. Therefore, in total, sodium iodide has 1 + 7 = 8 valence electrons.
No, sodium has 1 valence electron, not 3.
Na has one valence electron i.e. 1 electron in valence(last) shell.
To find the number of valence electrons of an element using the periodic table, you can look at the group number of the element. The group number indicates the number of valence electrons. For example, elements in Group 1 have 1 valence electron, elements in Group 2 have 2 valence electrons, and so on.
Through the number of electrons in the last (valence) shell. Delete Sodium has the electronic configuration 2, 8, 1; therefore it's valency is 1.