ps the world won't blow up- it's okay.
It is released as energy of fission fragments which then becomes thermal energy as the fragments are slowed down. Have you heard of E = MC2?
The lost mass (or mass defect) transforms into energy according to the law:
E = mc2
An alpha particle consists of 2 neutrons and 2 protons which are lost from the nucleus of the decaying particle so the mass of those particles is lost.
its converted to energy
The atomic mass number is the mass of the nucleus in atomic mass units.
Yes. An electron, one of those little negatively charged critters that forms up around the nucleus of an atom, has little mass compared to the nucleons. (Nucleons are protons and neutrons - the particles that make up the nucleus). In fact, the mass of an electron is less than 1/1800th the mass of a proton. All the electrons in any given atom account for only a tiny amount of the total mass of that atom. Almost all the mass is accounted for the protons and neutrons (if any) in the nucleus. It's that simple, and you already show that you know it.
1. The atomic number is equivalent to the number of protons in the atomic nucleus of a chemical element. The number of protons is identical for all the isotopes of an element. 2. The mass number is the sum of protons and neutrons in the atomic nucleus of an isotope.
Almost all of an atom's mass is in the nucleus.
Mass that is "lost" durning nuclear fusion is converted into binding energy to hold the newly formed atomic nucleus together. The lost mass, which is termed mass deficit, means the nucleus of the newly formed atom has less mass than the sum of the masses of the protons and neutrons that make up that nucleus. The stong reaction (strong nuclear force) participitates in the fursion reaction by mediating the conversion of mass into nuclear binding energy (or nuclear glue).It converts into the energy that is the desired end product of the reaction.
The lost mass (or mass defect) transforms into energy according to the law: E = mc2
The mass isn't really lost, it's converted to energy via E=mc². The same thing happens in chemical reactions, it's just not noticeable. For example, burning one mole of carbon produces about 393500 J. Using E=mc² 393500 J=m(3.00x10^8 m/s)² m=393500 J/(3.00x10^8 m/s)² =4.37x10^-12 Kg Note that a Joule(J) is a (Kg∙m²)/s² so that's why the units cancel out to give Kg. Anyways, you see that the mass "lost" is very small, if you don't understand how small 4.37x10^-12 Kg is, write it out, it's 0.00000000000437 Kg. A good analytical balance wouldn't even be able to detect such a small "loss" in mass. However when we're dealing with nuclear reactions we're usually talking about converting mass to energy and because E=mc² and the speed of light(c) is such a large number we get a lot of energy from a small "loss" in mass! That's the only reason we care about the small "loss" in mass when we're talking about nuclear reactions. Notice that I put the word "loss" in quotations because like I said, the mass is not really lost, it's just converted to energy.
A warm front forms.
An alpha particle consists of 2 neutrons and 2 protons which are lost from the nucleus of the decaying particle so the mass of those particles is lost.
If you are asking whether the nucleus' mass would increase, the answer is no. Beta decay involves emission of an electron from the nucleus. This happens when a neutron converts to a proton, an electron, and an anti-neutrino. A neutron is heavier than a proton, and the anti-neutrino carries away some energy with it, so the mass of the nucleus decreases.
its converted to energy
Proton number is decreased by two while mass number is decreased by four. Since alpha particle is similiar to helium nucleus.
An "occlusion" forms.
The atomic mass number is the mass of the nucleus in atomic mass units.
Yes, the great majority of the mass of an atom is in the nucleus.