it's divisible by 3 = 205.
but 615 is not divisible by 9
3
Divisible Pool= "Pool" from which money is shared between Federation and provinces
When a transposition error occurs on a trial balance, the difference between the debit and credit totals will always be a multiple of 9. This is because transposing two digits results in a number that, when subtracted from the original, will yield a difference that is divisible by 9. For example, if 54 is transposed to 45, the difference is 9, which is a multiple of 9.
3% + 1.32 (9 - 3)% = 10.92%
Non-divisible cost refers to expenses that cannot be divided or allocated on a per-unit basis, often associated with fixed costs that do not change with the level of production or output. These costs remain constant regardless of the number of units produced, making them difficult to assign to individual products or services. Examples include rent, salaries, and certain overhead expenses. Understanding non-divisible costs is crucial for businesses when analyzing profitability and making pricing decisions.
True. Since 615 ends in 5, it is divisible by 5. Since the sum 12, of the digits of 615, is divisible evenly by 3, 615 is divisible by 3.
No, any number which is perfectly divisible by 9 has its digits equal to a multiple of 9. The closest multiples of 9 to 615 are 612 and 621. (68 x 9 and 69 x 9 respectively).
1,845 is divisible by the following numbers: 1, 3, 5, 9, 15, 41, 45, 123, 205, 369, 615 and 1845.
615/5 = 123
615 ÷ 9 = 68 with remainder 3
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
9 is divisible by both 3 and 9
Three is divisible by 3 and 9.
If a number is not divisible by 3 then it is not divisible by 9.
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6