-- the initial horizontal speed of the projectile -- the time it remains in flight before it hits the ground
The horizontal speed of the projectile remains constant as there is no force acting in the horizontal direction to change it. Therefore, the horizontal speed of the projectile after 3 seconds will remain at 4 m/s.
The horizontal component of the initial velocity of the ball is the velocity in the horizontal direction at the moment the ball is launched. It represents the speed and direction at which the ball is moving side-to-side.
The speed will depend on its initial velocity and any forces acting on it.
The height reached by a ball thrown upward depends on its initial speed: the higher the initial speed, the higher the maximum height reached. This is because a greater initial speed gives the ball more kinetic energy, allowing it to overcome gravity and reach a higher position before gravity brings it back down.
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
Using the kinematic equation for projectile motion, the horizontal distance the ball traveled is given by the formula: (d = v_{i} \cdot t \cdot \cos(\theta)) where (v_{i}) is the initial speed, (t) is the time of flight, and (\theta) is the angle of projection. Plugging in the given values, we get: (d = 25 \cdot 2.55 \cdot \cos(35) \approx 49.6 , m)
Acceleration means that either the speed or the direction of motion changes. Acceleration requires force. When the thrust and drag are equal, the net horizontal force is zero, so there's no horizontal acceleration, meaning that the speed or direction of motion in the horizontal plane can't change. And you've already stipulated that the craft is in level flight, so we can't give it any vertical speed, or let it pitch (nose up or down). So according to the carefully crafted conditions of the question, the answer is 'no'.
The vertical speed of a horizontal taut string depends on the wave speed because the tension in the string is responsible for transmitting the wave along its length. The wave speed is determined by the tension in the string and the properties of the medium it is traveling through, which in turn affects the vertical motion of the string as the wave propagates.
(As usual when working with this subject, we'll assume zero air resistance.)When the projectile is launched, the horizontal component of its velocity is V0cos(A).At its highest point, its vertical speed is zero; all of its speed is horizontal,and equal to the horizontal speed it had coming out of the muzzle.V0/6 = V0cos(A)cos(A) = 1/6A = cos-1(1/6) = 80.4 degrees (rounded)
initial speed means first
Yes. They will both initially be moving at the same speed.