There are infinitely many ordered pairs. One of these is (0, 0).
I am sorry but the question is incomplete. You have not mentioned the ordered pairs and the equation is incomplete as well.
There are an infinite number of ordered pairs that satisfy the equation.
You didn't show the Ordered Pairs so there is no way this question could be answered.
Relationship can also be represented by a set of ordered pairs called a function.
The question does not contain an equation nor an inequality. There cannot, therefore be any ordered pairs which can satisfy an expression.
An exponential function can be represented in the form ( f(x) = ab^x ), where ( a ) is a constant and ( b ) is a positive real number. The set of ordered pairs generated by such a function will show a rapid increase or decrease, depending on whether ( b > 1 ) or ( 0 < b < 1 ). For example, the pairs ( (0, 1), (1, 2), (2, 4), (3, 8) ) could represent the exponential function ( f(x) = 2^x ). In contrast, a linear function would produce pairs with a constant difference in the ( y )-values as ( x ) increases.
There are infinitely many ordered pairs. One of these is (0, 0).
If a set of ordered pairs is not a relation, the set can still be a function.
I am sorry but the question is incomplete. You have not mentioned the ordered pairs and the equation is incomplete as well.
3x
There are an infinite number of ordered pairs that satisfy the equation.
The question cannot be answered unless a specific equation is cited.
You didn't show the Ordered Pairs so there is no way this question could be answered.
Relationship can also be represented by a set of ordered pairs called a function.
The function in algebra of ordered pairs is function notation. For example, it would be written out like: f(x)=3x/4 if you wanted to know three fourths of a number.
1,6 2,12 3,18 4,24 5,30