IGNORE OLD ANSWER y=2
z=3
work:
3y=2z=12
y-z=9
multiply y-z=9 by -3
3y+2z=12
-3y+3z=-27
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5z=-15
z=3
substitute 3 for z
3y+2(3)=12
3y=6
y=2
16
(2,3)
The solutions are: x = -2 and y = 4
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.
{-1,-2}
x = 4 and y = 0
the answer
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.
x = -1.2, y = -3
a=5: c=4
To solve for two unknowns (x and y) it is necessary to have two independent equations.
x = 6 and y = -2
(0,7)
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
16
When talking about a "system of equations", you would normally expect to have two or more equations. It is quite common to have as many equations as you have variables, so in this case you should have two equations.
(2,3)