At x = 3, the value of F(x) = 3x + 2 is the value 11, which graphs to the point (3, 11).
x = 7 and 2/3
5=3x+2 3x+2-2=5-2 3x=3 ------ 3 x=1
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
3x+2 = 5x so 2x = 2 and hence x = 2/2 = 1
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3
y = 3x + 2x^2 + k where k is any number
17
3x + 2 = 3x + 6 This is not possible.
(2, -1)
Their graphs are.
The function f(x) = 3x + 2 can take any real value, so the question does not seem to make any sense.
3x + 2 = 0 3x = -2 x = -2/3
4x plus 7 plus 3x equals 19 plus xx = 2
3x + 2 = -10 3x = -12 x = -4
x = 7 and 2/3
3x + 2 = Y
(-2, 4)