library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL;
use IEEE.STD_LOGIC_UNSIGNED.ALL;
entity mux2x1 is
Port ( i : in STD_LOGIC_VECTOR (1 downto 0);
s : in STD_LOGIC;
y : out STD_LOGIC);
end mux2x1;
architecture df of mux2x1 is
begin
with s select
y<= i(0) when '0',
i(1) when '1',
'0' when others;
end df;
Since a fulladder can be obtained by using 2 halfadders & 1 OR gate.....so we have to call an halfadder program as well as an OR program......this can be implemented easily with the help of structural model rather than dataflow and behavoioural model
library IEEE;use IEEE.STD_LOGIC_1164.ALL;use IEEE.STD_LOGIC_ARITH.ALL;use IEEE.STD_LOGIC_UNSIGNED.ALL;entity pa isPort ( a : in STD_LOGIC_VECTOR (3 downto 0);b : in STD_LOGIC_VECTOR (3 downto 0);ci : in STD_LOGIC;co : out STD_LOGIC;s : out STD_LOGIC_VECTOR (3 downto 0));end pa;architecture Behavioral of pa is--signal declarationsignal c:std_logic_vector(2 downto 0);--component declarationcomponent fadfPort ( ain : in STD_LOGIC;bin : in STD_LOGIC;cin : in STD_LOGIC;sum : out STD_LOGIC;cout : out STD_LOGIC);end component;beginu0:fadf port map(a(0),b(0),ci,s(0),c(0));u1:fadf port map(a(1),b(1),c(0),s(1),c(1));u2:fadf port map(a(2),b(2),c(1),s(2),c(2));u3:fadf port map(a(3),b(3),c(2),s(3),co);end Behavioral;
4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6
1/2
1 1/2 + 1 1/2 Hope it helps! Also try: 1 1/4 + 1 3/4
A structural VHDL program for an 8-to-1 multiplexer defines the multiplexer using lower-level components, such as 2-to-1 multiplexers. You can instantiate several 2-to-1 multiplexers to create the 8-to-1 functionality. The 8 input signals are combined through three levels of 2-to-1 multiplexers, where the first level reduces the inputs from 8 to 4, the second from 4 to 2, and the final level selects the output from 2 inputs. Below is a simple structural VHDL example: library IEEE; use IEEE.STD_LOGIC_1164.ALL; entity MUX8to1 is Port ( A : in STD_LOGIC_VECTOR(7 downto 0); S : in STD_LOGIC_VECTOR(2 downto 0); Y : out STD_LOGIC); end MUX8to1; architecture Structural of MUX8to1 is signal MUX1_out, MUX2_out, MUX3_out, MUX4_out : STD_LOGIC; begin MUX1: entity work.MUX2to1 port map (A(0), A(1), S(0), MUX1_out); MUX2: entity work.MUX2to1 port map (A(2), A(3), S(0), MUX2_out); MUX3: entity work.MUX2to1 port map (A(4), A(5), S(0), MUX3_out); MUX4: entity work.MUX2to1 port map (A(6), A(7), S(0), MUX4_out); MUX5: entity work.MUX2to1 port map (MUX1_out, MUX2_out, S(1), Y_temp1); MUX6: entity work.MUX2to1 port map (MUX3_out, MUX4_out, S(1), Y_temp2); MUX7: entity work.MUX2to1 port map (Y_temp1, Y_temp2, S(2), Y); end Structural; In this example, MUX2to1 is a previously defined 2-to-1 multiplexer entity. Each level of multiplexing reduces the number of inputs until the final output is selected based on the 3-bit select signal S.
VHDL is a hardware description language. You can describe the hardware in three different ways using VHDL. 1. dataflow model 2. behavioral model 3. structural model
Use the multiplexer to choose the correct output based on the inputs (use the truth table).
Vhdl has got three models - programming styles. 1. data flow model 2. behavioral model 3. structural model.
help
You don't need two 4-to-1 multiplexers. You only need one 4-to-1 multiplexer, and something that functions as a 2-to-1, like a single 2-input OR gate with one input grounded.
Since a fulladder can be obtained by using 2 halfadders & 1 OR gate.....so we have to call an halfadder program as well as an OR program......this can be implemented easily with the help of structural model rather than dataflow and behavoioural model
library ieee;
1)Home Security based system 2)ROM Based Sine wave
Jo MUX hai wo circuit ki tarah karya karta hai. adhik jankari ke liye csa ki book search kre. Deepak Shukla. Duble MCA-
15 2 bit multiplexers
Type your answer here... D0-D7 on 1st 8to1, D8-D15 on 2nd 8to1, S0,S1,S2 to both. The output from 1st 8to1 is D0 on the 2to1, the output from the 2nd 8to1 is D1 on the 2to1 and S3 to the 2to1. The 2to1 provides the final 16to 1 mutiplexed output, OK?